我的HTML按钮无法打开PHP链接
[英]My HTML button won't open PHP link
问题描述
I'm trying to invoke a PHP script from my HTML file. 
我正在尝试从HTML文件中调用PHP脚本。
Following is my HTML code: 以下是我的HTML代码：
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Welcome to B.O.A.T</title>
<link rel="stylesheet" type="text/css" href="CSS/css.css" />
<meta name="viewport" content="width=device-width, initial-scale=1.0" />
</head>
<body>
<!-- Navigation Bar -->
<div class="tab_content">
<div id="home" class="tab_active">
<div id="banner-container">
<div id="banner">
<p id="boat-banner"> Welcome to Bike Operation Automation Technology </p>
</div>
</div>
<div id="buttons">
<form method="post" action="lock.php">
<input type="button" name="Lock" class="button" value="LOCK" />
</form>
<form method="post" action="unlock.php">
<input type="button" name="Lock" class="button" value="UNLOCK" />
</form>
<form method="post" action="ledOn.php">
<input type="button" name="Lock" class="button" value="IGNITION ON" />
</form>
<form method="post" action="ledOff.php">
<input type="button" name="Lock" class="button" value="IGNITION OFF" />
</form>
<form method="post" action="GPSTracker.php">
<input type="submit" name="GPSTracker" class="button" value="GPS TRACKER"/>
</form>
</div>
</div>
</div>
</body>
</html>
Following is my ledOn.php file that I want to invoke (It's one of those PHP scripts that are not being invoked) 以下是我要调用的ledOn.php文件（这是未调用的PHP脚本之一）
<html>
<head>
<title>LEDON</title>
</head>
<body>
<?php
define('HOST','mysql.hostinger.in');
define('USER','u414932932_usr');
define('PASS','xyz123');
define('DB','u414932932_bdb');
$con = mysqli_connect(HOST,USER,PASS,DB);
//$ign = $_POST['ignition'];
$sql = "UPDATE BOATOP SET ignition='1' WHERE user_name='boatusr'";
if(mysqli_query($con,$sql))
{
echo 'SUCCESS'; ?>
<H3> SUCESS </H3>
<?php
}
else
{
echo "FAILURE";
?>
<H3> FAILURE </H3>
<?php
}
mysqli_close($con);
?>
</body>
</html>
When I click the Ignition On button, nothing happens. 当我单击“ 点火开关”按钮时，什么也没有发生。 I don't understand.. Neither do any of the other buttons open their respective PHP files. 我不明白。其他按钮也不打开各自的PHP文件。 Where am I going wrong? 我要去哪里错了？
4 个解决方案
解决方案1
2 2016-06-09 02:18:56
it's an input type="button" which won't submit the form. 这是输入type="button" ，它不会提交表单。 these should be type="submit" 这些应该是type="submit"
<div id="buttons">
<form method="post" action="lock.php">
<input type="submit" name="Lock" class="button" value="LOCK" />
</form>
<form method="post" action="unlock.php">
<input type="submit" name="Lock" class="button" value="UNLOCK" />
</form>
<form method="post" action="ledOn.php">
<input type="submit" name="Lock" class="button" value="IGNITION ON" />
</form>
<form method="post" action="ledOff.php">
<input type="submit" name="Lock" class="button" value="IGNITION OFF" />
</form>
<form method="post" action="GPSTracker.php">
<input type="submit" name="GPSTracker" class="button" value="GPS TRACKER"/>
</form>
</div>
解决方案2
1 2016-06-09 05:26:16
Edit: Someone has pointed out that, we can use input type submit or button type submit. 编辑：有人指出，我们可以使用输入类型提交或按钮类型提交。
Functionality wise, they are the same but buttons created with button element offer richer rendering possibilities. 在功能上，它们是相同的，但是使用按钮元素创建的按钮提供了更丰富的渲染可能性。
https://www.w3.org/TR/html4/interact/forms.html#h-17.5 https://www.w3.org/TR/html4/interact/forms.html#h-17.5
<div id="buttons">
<form method="post" action="lock.php">
<button type="submit" class="button" value="lock"> LOCK </button>
</form>
<form method="post" action="unlock.php">
<button type="submit" class="button" value="unlock"> UNLOCK </button>
</form>
<form method="post" action="ledOn.php">
<button type="submit" class="button" value="on"> IGNITION ON </button>
</form>
<form method="post" action="ledOff.php">
<button type="submit" class="button" value="off"> IGNITION OFF</button>
</form>
<form method="post" action="GPSTracker.php">
<button type="submit" class="button" value="gps'> GPSTracker </button>
</form>
</div>
解决方案3
0 2016-06-09 05:33:26
It looks to me like you will be well-served using links instead of buttons for what you are trying to do since there is absolutely no data inside the forms that you are using. 在我看来，由于要使用的链接而不是按钮，您会得到很好的服务，因为您使用的表单中绝对没有数据。
<form method="post" action="ledOn.php">
<button type="submit" class="button" value="on"> IGNITION ON </button>
</form>
can become 可以变成
<a href="ledOn.php">
IGNITION ON
</a>
解决方案4
0 2016-06-09 05:40:51
You can do this in two ways 您可以通过两种方式执行此操作
1) Need to change the button into input type submit like you did for last form:- 1）需要像上次表单一样将按钮更改为输入类型提交：
<input type="submit" name="GPSTracker" class="button" value="GPS TRACKER"/>
2) You need to use jQuery for this you need to add id in the form and click event on button like:- 2）为此，您需要使用jQuery，您需要在表单中添加id并单击按钮上的事件，例如：
<form method="post" action="lock.php" id="form_id">
<input type="button" name="Lock" class="button" value="LOCK" onclick=" $('#form_id').submit();" />
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