为什么要执行此功能？

Question

I need help with understanding how the following script is working.

var foo = function() {
    console.log("A");
}

(function() {
    // Empty
})

When running this script with node (v5.9.1) the output is "A" . I would expect it to just do nothing. Why is foo executed here? I can either delete the first or last three lines and then there is no output.

• Edit: it works as expected if I place a ; after the curly bracket on line 3. But why?

Answer 1

If you put (...) immediately after a function expression, you execute that function.

The code in the question defines a function which calls console.log . Then it calls that function (passing it an argument (which isn't used) of a function which does nothing anyway). Then it assigns the return value of calling the first function to foo .

It could be rewritten as:

var function_a = function() {console.log("A");};
var function_b = function() {};
var foo = function_a(function_b);

… with the only side effects being the creation of the function_a and function_b variables.

---

Semi-colon insertion is usually considered harmful because it leads people to expect whitespace to separate the statement into two unrelated expressions.

JSHint would warn you of the problem:

7 Missing semicolon.

Answer 2

JavaScript将(...)解释为对先前定义的函数的调用（请注意，您将另一个函数作为参数传递，在foo中被忽略），因为}和(符号之间没有任何内容）。

Answer 3

With your code

var foo = function() {
    console.log("A");
}

(function() {
    // Empty
})

the javascript interpreter is reading this :

var foo = function() {
    console.log("A");
}(function() {});

For the interpreter you declared an anonymous function, and pass it a parameter and it returns nothing, then value of foo is undefined

That's why it is very important to put ; in each end of line when it is neccessary.