使用sed替换字符串中的版本号

Question

I have a bundle version set in a file, like this:

"dist/app-build-v1.08": {

How can I sed the version number and swap it out with an incremented number?

First I'm attempting to grab the line itself, which is the third line in my bundle file.

BUILD=$(sed '3q;d' ./build/bundles.js)

Which does indeed grab the line. I found this snippet here on stack overflow:

's/[^0-9.]*\([0-9.]*\).*/\1/'

Which i'd like to use on $BUILD, but it doesn't work. The expected output for me would be

$NUM = "1.08"

Then I'd like increment it to 1.09, rebuild the string and used sed -i to replace it.

Answer 1

It seems that the interesting line is always line 3. Then you can use this awk one-liner:

awk 'NR==3{gsub(/[^.0-9]+/,"");$0+=0.01;print}' file.js

• This line focuses on line3, and take the version number, add 0.01 to it.
• Assume that your version format is always x.xx . If it is not in this case, it is also possible to calculate the increment dynamically. like 0.01 or 0.00001 But extra implementation is required.
• If you run it with your example file, it will give you 1.09

Answer 2

Another way :

sed -r '3s/.*build-v([0-9]+(\.[0-9]+)?).*/\1+0.01/' | bc -q

Example:

$ echo '"dist/app-build-v1.08": {' | sed -r 's/.*build-v([0-9]+(\.[0-9]+)?).*/\1+0.01/' | bc -q
1.09