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如果记录不存在,MongoDB find 不会返回错误?

[英]MongoDB find doesn't return an error if a record doesn't exist?

I'm using Mongoose:我正在使用猫鼬:

user.find({username: 'xyz'}, function(err, doc){
  if(err){
    res.render('error', {errorMsg: "Error blah blah"})
  }
});

I'm deliberately using a user who doesn't exist xyz and it's not triggering any errors, I thought it was because of Mongoose but then I tried in MongoDB shell and yes MongoDB won't return an error if a record doesn't exist.我故意使用一个不存在 xyz 的用户,它没有触发任何错误,我以为是因为 Mongoose,但后来我在 MongoDB shell 中尝试,是的,如果记录不存在,MongoDB 不会返回错误.

>db.accounts.find({username: 'xyz'})
> // no error, blank line

How do I handle that?我该如何处理? I want the execution of the script stop if a user doesn't exist.如果用户不存在,我希望脚本停止执行。

Well, if the "username" doesn't exist, that doesn't mean there is an error.好吧,如果“用户名”不存在,这并不意味着有错误。 Instead you should do something like this.相反,你应该做这样的事情。

user.find({ username: 'xyz' }, function(err, doc){
  if(doc.length === 0 || err){
    res.render('error', { errorMsg: "Error blah blah" } )
  }
});

Or more verbose version:或更详细的版本:

user.find({ username: 'xyz' }, function(err, doc) {
    if(err){
        res.render('error', { errorMsg: "Error blah blah" } )
    } else {
        if (doc.length === 0) {
            console.log("User doesn't exist");
        } else {
            //do something
        }
    }
});
var user = db.accounts.findOne({username: 'xyz'});

if (!user) {
   // handle error
   alert('fail');
}

Try to check if the doc is null or not first and then you can get on with your function.首先尝试检查文档是否为空,然后您可以继续使用您的功能。

user.find({ username: 'xyz' }, function(err, doc){
   if(doc === null || err){
      res.render('error', { errorMsg: "Error blah blah" } )
   }
   else {
      do something...
    }
});

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