CakePHP-在find（）方法中从JOIN中排除模型

Question

I'm currently working on a project with CakePHP and its find() method to handle database queries.

My current situation is as follows:

I have 3 Models: User , Location and Order . The connection is that a User hasOne Location and User hasMany Orders .

When I'm using the find() method to get the User and the address (stored in the Location model) CakePHP returns the User, Location, and the Order Models. In my case, I don't need the Order information.

So my question is: Is it possible to tell CakePHP not to join with the Order Model?

I know about the recursive attribute, but if I set it to -1 , CakePHP returns just the User Model and in the case of recursive >= 0, it returns all 3 Models.

Answer 1

Solved problem with Containable of cakephp. The code is as follows:

$this->User->Behaviors->load('Containable');

$this->User->recursive = -1;
$this->paginate = array('fields' => array('User.*'),
                        'contain' => array('Location'=>array('field1', 'field2')
                       );

$user = $this->Paginator->paginate('User');

Answer 2

You can use unbind model function to exclude desired models

In your case :

$this->User->unbindModel(array('hasMany' => 'Orders'));

For common

$this->User->unbindModel(
            array(
                'hasMany' => array('Model1','Model2'),
                'hasOne' => array('Model1','Model2'),
                'belongsTo' => array('Model1','Model2'),
                )
        );