如何通过一个输入从两个不同的表中获得结果

Question

I have two different tables with different column name

Table 1 users

+-----+----------+---------+---------+------------+
|  id |   name   | username| image   |   email    |
+-----+----------+---------+---------+------------+
|  1  |  John1   | exmple1 |  img1   |a@gmail.com |
|  2  |  John2   | exmple2 |  img2   |b@gmail.com |
|  3  |  John3   | exmple3 |  img3   |c@gmail.com |
|  4  |  John4   | exmple4 |  img4   |d@gmail.com |
+-----+----------+---------+---------+------------+

Table 2nd Company

+-----+----------+------------+---------=------+-----------+
|  id |company_name | username|  description   |   founded |
+-----+-------------+---------+----------------+-----------|
|  1  |    john1    | exmple1 |description1    |    2016   |
|  2  |CompanyName2 | exmple2 |description2    |    2016   |
|  3  |CompanyName3 | exmple3 |description3    |    2016   |
|  4  |CompanyName4 | exmple4 |description4    |    2016   |
+-----+-------------+---------+---------=------+-----------+

Now whenever a user type any input in search bar an ajax request is made to php file which checks for if that name of user exist in database or not

so for example if user type input john then a query should run which will check john in users table and company table & if there is a user name john & if there is a company named john it should fetch both the result.

how can i achieve this, i tried using UNION in my query but it said columns are different

Currently this is my query

$go = mysqli_query($connecDB, "SELECT name, img,username FROM users WHERE name LIKE '$q%' LIMIT 0,10");

Now people might be thinking what i really want! i want a single query that will check for input in both table & fetch their details

Answer 1

You can use union

select  id,  name  ,username, image, email, null, null
from users
where name LIKE concat('$q', '%')
union all
select  id,  company_name as name  ,username, null, null, description, founded 
from Company 
where name LIKE concat('$q, '%')
order by name limit 10