[英]url.openConnection(); is not actually invoked
Im building a graduation project for my collage about "Smart Homes, Home Automation System" implemented with Arduion on a mock-up structure. 我为拼贴画设计了一个毕业项目,该项目与Arduion在模型结构上实现的“智能家居,家庭自动化系统”有关。
To have the full image, the Arduaio takes the pin number via a get request to switch on or of a specific home device. 为了获得完整的图像,Arduaio通过获取请求来打开特定家用设备的针脚号。
its all cool when i send the HTTP request from any browser, but when i use the 当我从任何浏览器发送HTTP请求时,一切都很酷,但是当我使用
openConnection();
method, it's like something never happens, but when i use it to get some data about the home rooms and its devices it's working greatly. 方法,就像从未发生过任何事,但是当我使用它来获取有关家庭房间及其设备的一些数据时,它的工作效率很高。
i already gave the app the permission to access the internet. 我已经授予该应用访问互联网的权限。
the code from a simple project i made just to solve this praticualy problem: 我为解决这个普遍存在的问题而编写的一个简单项目中的代码:
MainActivity.java
MainActivity.java
package com.bitsandbytes.xemma_pc.newprototype;
import android.os.AsyncTask;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import java.io.IOException;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Button button = (Button) findViewById(R.id.button);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
new SendRequest().execute();
}
});
}
private static class SendRequest extends AsyncTask <Void,Void,Void>{
@Override
protected Void doInBackground(Void... params) {
HttpURLConnection httpURLConnection = null ;
URL url ;
try {
url = new URL("http://192.168.1.143/pin=13");
httpURLConnection = (HttpURLConnection) url.openConnection();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}finally {
httpURLConnection.disconnect();
}
return null;
}
}
}
activity_main.xml
activity_main.xml
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context="com.bitsandbytes.xemma_pc.newprototype.MainActivity">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textAppearance="?android:attr/textAppearanceLarge"
android:text="Press it to Test it"
android:id="@+id/textView"
android:layout_marginTop="154dp"
android:layout_alignParentTop="true"
android:layout_centerHorizontal="true" />
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Pin 13"
android:id="@+id/button"
android:layout_below="@+id/textView"
android:layout_centerHorizontal="true" />
</RelativeLayout>
AndroidManifist.xml
AndroidManifist.xml
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.bitsandbytes.xemma_pc.newprototype">
<uses-permission android:name="android.permission.INTERNET"/>
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity android:name=".MainActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
i appreciate the help and the tips in advance. 我先感谢帮助和提示。
EDIT: thanks you guys for helping me, but what it really helped me was using the getResponseMessage() method, and it works greatly :D i didn't have to use .connect method to get some JSON strings before, but it was working. 编辑:谢谢你们对我的帮助,但真正帮助我的是使用getResponseMessage()方法,它的工作原理非常好:D我以前不必使用.connect方法来获取一些JSON字符串,但它确实有效。 anyway, thanks for the help!
无论如何,谢谢您的帮助!
openConnection
just parses the URL and creates the appropriate URLConnection
subclass. openConnection
只是解析URL并创建适当的URLConnection
子类。 Network I/O doesn't happen until you send or receive something. 在您发送或接收消息之前,不会发生网络I / O。
You need to read the data and then network IO will occur. 您需要读取数据,然后将发生网络IO。
String response = "";
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
// Set Method here
conn.setRequestMethod("POST");
InputStreamReader in = new InputStreamReader(conn.getInputStream());
BufferedReader br = new BufferedReader(in);
String line= "";
while ((line= br.readLine()) != null) {
response += line;
}
conn.disconnect();
URL.openConnection()
only returns a URLConnection
to the specified resource. URL.openConnection()
仅将URLConnection
返回到指定资源。
You can open an actual connection to that resource by calling the connect()
method of that particular URLConnection
. 您可以通过调用特定
URLConnection
的connect()
方法来打开与该资源的实际连接。
For example: 例如:
HttpURLConnection connection = (HttpURLConnection) someUrl.openConnection();
connection.connect();
Operations that require a connection (like getInputStream()
or getOutputStream()
) will implicitly call connect()
, so explicitly calling it before such operations is not necessary: 需要连接的操作(如
getInputStream()
或getOutputStream()
)将隐式调用connect()
,因此无需在此类操作之前显式调用它:
HttpURLConnection connection = (HttpURLConnection) someUrl.openConnection();
connection.connect(); // this is redundant
connection.getInputStream(); // getInputStream() will call connect()
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