[英]get last date in month error
I have the following code which gets the date parsed, the subtracts 1 month. 我有以下代码,该代码获取解析的日期,减去1个月。 This works perfectly.
这很完美。
$date = '22-05-2016';
print(date("Y-m-d 23:59:59", strtotime($date.' -1 months')));
// outputs 2016-04-22 23:59:59
There are times where I need to force the date to month end. 有时我需要将日期强制为月底。 For this I use
Ymt
instead of Ymd
Which works perfectly. 为此,我使用
Ymt
而不是Ymd
它可以很好地工作。
$date = '22-05-2016';
print(date("Y-m-t 23:59:59", strtotime($date.' -1 months')));
// outputs 2016-04-30 23:59:59
$date = '31-05-2016'; print(date("Ymt 23:59:59", strtotime($date.' -1 months')));
Actual Output 2016-05-31 23:59:59 (hasn't removed 1 month) 实际输出2016-05-31 23:59:59 (1个月未移除)
Desired Output 2016-04-30 23:59:59 期望的输出2016-04-30 23:59:59
EDIT: Fiddle example http://ideone.com/0fqlor 编辑: 小提琴示例http://ideone.com/0fqlor
Try: 尝试:
$date = '31-05-2016';
print(date("Y-m-d 23:59:59", strtotime($date.' last day of last month')));
and dig into strtotime
possibilities ;) 并探讨
strtotime
可能性;)
Take a look here: http://php.net/manual/en/datetime.formats.relative.php 在这里看看: http : //php.net/manual/en/datetime.formats.relative.php
Last Note: -1 month
only gets 30 days back in time. 最后注意事项:
-1 month
只能恢复30天。 Therefore it will not work allways. 因此,它将无法正常工作。 Some kind of PHP stuff, i think ;)
我认为有些PHP的东西;)
strtotime
is your friend. strtotime
是您的朋友。 The last day of any "given" month can be retrieved using the verbal String last day of May 2015
- so, for easy input (guess you have a date-picker not a month-picker), convert the selected date to its month expression first: 可以使用
last day of May 2015
年last day of May 2015
的语言字符串来检索任何“给定”月份的last day of May 2015
-因此,为了方便输入(猜测您使用日期选择器而不是月份选择器),请将所选日期转换为其月份表达式第一:
date_default_timezone_set('Europe/London');
$to = '31-05-2016';
$month = date("M Y", strtotime($to));
$strtotime_expression = "last day of " . $month;
echo $strtotime_expression.": <br />";
print(date("Y-m-t 23:59:59", strtotime($strtotime_expression)));
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