有没有办法判断一个枚举是否只设置了一个，多个或没有标志？

Question

I have an enum defined like that:

[Flags]
public enum Orientation
{
    North = 1,
    North_East = 2,
    East = 4,
    South_East = 8,
    South = 16,
    South_West = 32,
    West = 64,
    North_West = 128
}

Is there a generic way to tell if exactly one flag is set, multiple or none? I don't care for what the value of the enum is, I just want to know how many flags are set.

This is not a duplicate for counting the number of bits. If I initialize the enum like this and count the number of bits I get 10. But the number of set flags would be 8.

GeographicOrientation go = (GeographicOrientation) 1023;

Answer 1

you can use this code :

var item = Orientation.North | Orientation.South;
int i = 0;
foreach (Orientation e in Enum.GetValues(typeof(Orientation)))
    if(item.HasFlag(e))
        i++;

Console.WriteLine(i);

Answer 2

var test = Orientation.North;
var flagCount = GetFlagCount(test);

public int GetFlagCount(Enum testValue)
{
    return Enum.GetValues(testValue.GetType()).Cast<Enum>().Count(testValue.HasFlag);
}

Answer 3

If you are looking for the "shortest" way:

Orientation o = Orientation.East | Orientation.West;   // o.ToString() = "East, West"
var c = o.ToString().Split().Count(); 

or even shorter:

var c = (o + "").Split().Count(); 

Update

To support values above 255, you can use any of those ugly hacks:

Orientation o = (Orientation) 1023;   
var c = ((Orientation)(byte)o + "").Split().Count();
c = ((Orientation)((int)o & 255) + "").Split().Count();

or just define the enum as byte:

    [Flags]
    public enum Orientation : byte
    {
        North = 1,
        North_East = 2,
        East = 4,
        South_East = 8,
        South = 16,
        South_West = 32,
        West = 64,
        North_West = 128
    }

Update 2 I personally wouldn't use the string method in production code especially when just a bit count is needed.

Anyway, I just thought of another hack just for fun. Base 2 log will return a whole number when one bit is set, -Infinity when 0, and anything else when more than one bit is set. For Example

 Math.Log(0, 2 ) // -Infinity
 Math.Log(0, 64) // 6.0
 Math.Log(0, 65) // 6.0223678130284544

So, (byte)go != 0 can be used to check if any flags are set, and then Math.Log((byte)go, 2) % 1 == 0 to check if only one flag is set.

But, dasblinkenlight's solution seems like the best.

Answer 4

Off the top of my head:

var map = 1;
var count = 0;

while (map <= North_West)
{
    if( ((int)Value & map) > 0) 
       count += 1; 
    map = map << 1; //left shift, a.k.a. multiply by 2
}

Answer 5

You can determine this with a simple bit trick after converting the value to int :

int v = (int)enumValue;

1. If v == 0 , then no flags are set
2. Otherwise, if ((v-1)&v) == 0 , then exactly one flag is set
3. Otherwise, multiple flags are set.

The only tricky one is #2. Here is an explanation: consider a binary number with exactly one bit set to 1 . Then subtracting 1 would make the following change:

  0000010000000
-             1
  -------------
  0000001111111

All zeros following the lone 1 become 1 s, 1 becomes zero, and the rest of the bits remain the same. AND -ing v and v-1 produces zero, because there is no pair of 1 s in the same position between the two numbers.

When there are two or more 1 s, the bits to the left of the lone 1 will remain unchanged. Therefore, at least one position will have a 1 in the result of bitwise AND .

Answer 6

This is not a duplicate for counting the number of bits. If I initialize the enum like this and count the number of bits I get 10. But the number of set flags would be 8.

Please consider this statement directly from MSDN :

Flags enumerations are used for masking bit fields and doing bitwise comparisons .

If you are designing or using the enum in some manner that does NOT allow counting the number of flags using bitwise operations, then you are designing or using the enum improperly.

    [Flags]
    public enum MyEnum
    {
        Foo = 1,
        Bar = 2,
        Bizz = 4,
        Buzz = 8,
        Boo = 16
    }


var foo = MyEnum.Foo | MyEnum.Foo | MyEnum.Bizz;
// foo == MyEnum.Foo | MyEnum.Bizz because setting the same flag twice does nothing

var bar = (MyEnum)27 // Some invalid combination
// bar == 27.  Why would you do this instead of MyEnum.Boo | MyEnum.Buzz | MyEnum.Bar | MyEnum.Foo

If you design your enum properly, you can count the flag, and optionally short circuit if there is more than one flag set since continuing to count would be pointless.

        var foo = MyEnum.Foo | MyEnum.Bizz;
        int fooValue = (int)foo;
        int numberOfFlags = 0;

        while (fooValue > 0 && numberOfFlags < 2) // Stop counting if more than one flag since we don't need exact count
        {
            if ((fooValue & 1) == 1)
            {
                numberOfFlags++;
            }

            fooValue >>= 1;
        }

        Console.WriteLine(numberOfFlags);