[英]AJAX post jQuery to PHP $_POST
I have this modal jQuery AJAX: 我有这个模态jQuery AJAX:
$('#switch_modal').on('show.bs.modal', function (e) {
var rowid = $(e.relatedTarget).attr('data-id');
$.ajax({
type : 'post', // commented for this demo
url : 'pars.php', // commented for this demo
data : 'id='+ rowid,
success : function(data) {
$('.fetched-data').show().html(rowid); // show rowid for this demo
}
});
});
My mysql query: 我的mysql查询:
$query="SELECT * FROM games WHERE winner='' ORDER BY amount DESC";
while ($row = $result->fetch_assoc()) {
My modal data-id: 我的模态数据ID:
<a href="#viewgame" data-toggle="modal" data-id="<?php echo $row['id'];?>"">
How can i do to use the var rowid like a PHP post? 我该如何像php post一样使用var rowid? Something like that:
像这样:
$id = $_POST['rowid'];
echo $id;
If i understand well this test your doing... 如果我理解得很好,请测试您的操作...
Your JavaScript rowid
is the value. 您的JavaScript
rowid
是值。 The $_POST
identifier is id
. $_POST
标识符是id
。
Try this in your PHP: 在您的PHP中尝试一下:
$id = $_POST['id'];
echo $id;
You'll get the javascript rowid
sent as a POST value (named as $_POST['id']
) via ajax... 您将通过ajax获取以POST值发送的javascript
rowid
(名为$_POST['id']
)...
And returning in data
on ajax success. 并返回有关ajax成功的
data
。
$('.fetched-data').show().html(data);
So you'll have to use data
in your jQuery html()
... Wich is the echoed text. 因此,您将不得不在jQuery
html()
使用data
。Wich是回显的文本。
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EDIT AFTER ACCEPTATION of this answer 接受此答案后编辑
(Based on your last comment) (根据您的最新评论)
So i have this query:
所以我有这个查询:
$query="SELECT * FROM games WHERE winner='' ORDER BY amount DESC"; if ($result = $conn->query($query)) { while ($row = $result->fetch_assoc()) { $gameid = $row['id']; } }
So i want to use $gameid variable into this query:
所以我想在此查询中使用$ gameid变量:
$sql = "SELECT * FROM games WHERE id='".$gameid."'";
I understand, that you want to get THE LAST matching full line where winner value is empty from games table. 我了解,您想获得最后匹配的完整行 ,其中游戏表中的获胜者值为空。
No need for an ajax call... 不需要ajax调用...
No need for a second query. 无需第二次查询。
Just do it: 去做就对了:
$query="SELECT * FROM games WHERE winner='' ORDER BY amount DESC";
$result = $conn->query($query);
$row = $result->fetch_assoc();
for ($i=0;$i<sizeOf($row);$i++){ // This is the «size» (number of values) of one row, the last fetched.
echo $row[$i] . "<br>";
}
You'll get all your line values echoed... 您将得到所有行值的回显...
This will be the LAST matching line fetched. 这将是最后获取的匹配行。
If you have many matching lines and want all results, do it like this: 如果您有许多匹配的行并想要所有结果,请按以下步骤进行:
$query="SELECT * FROM games WHERE winner='' ORDER BY amount DESC";
$result = $conn->query($query));
while ($row = $result->fetch_assoc()) { // While fetching, echo all values of one matching line.
echo "row id: " . $row['id'] . "<br>";
echo "values: <br>";
for ($i=0;$i<sizeOf($row);$i++){
echo $row[$i] . "<br>";
}
}
Notice that this script, that I suggest, will enlight you about the while fetch loop
possible results. 请注意 ,我建议使用此脚本来启发您了解
while fetch loop
可能结果。 You'll have to work a little to have it displayed correctly on your page. 您需要做一些工作才能使其正确显示在页面上。
;) ;)
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