如何计算JavaScript数组中的字符？

Question

I need to count the characters from a to z in an array.

For example I have an array like this:

["max","mona"]

The desired result would be something like this:

a=2, m=2, n=1, o=1, x=1

It would be great, if anyone could help me :)

Answer 1

You can use two forEach loops and return object

 var ar = ["max", "mona"], o = {} ar.forEach(function(w) { w.split('').forEach(function(e) { return o[e] = (o[e] || 0) + 1; }); }); console.log(o) 

Or with ES6 you can use arrow function

 var ar = ["max","mona"], o = {} ar.forEach(w => w.split('').forEach(e => o[e] = (o[e] || 0)+1)); console.log(o) 

As @Alex.S suggested you can first use join() to return string, then split() to return array and then you can also use reduce() and return object.

 var ar = ["max", "mona"]; var result = ar.join('').split('').reduce(function(o, e) { return o[e] = (o[e] || 0) + 1, o }, {}); console.log(result) 

Answer 2

You can use just one forEach loop and return object

var ar = [ "bonjour", "coucou"], map = {};
ar.join("").split("").forEach(e => map[e] = (map[e] || 0)+1);
console.log(map);

Live Demo

https://repl.it/C17p

Answer 3

I would do it like this;

 var a = ["max","mona"], charCount = a.reduce((p,w) => w.split("").reduce((t,c) => (t[c] ? t[c]++: t[c] = 1,t),p),{}); console.log(charCount); 

Answer 4

public static void main (String[] args) throws java.lang.Exception
{
    String[] original = {"The","Quick","Brown","Fox","Jumps","Over","The","Lazy","Dog"};
    String singleString ="";
    for(String str : original )
    {
        singleString += str;
    }
     System.out.println(singleString);
    char[] chars = singleString.toLowerCase().toCharArray();
    Arrays.sort(chars);
    String result="";

    for(int i=0;i<chars.length;)
    {
    result += chars[i]+"=";
        int count=0;
        do {
            count++;
            i++;
            } while (i<chars.length-1 && chars[i-1]==chars[i]);

        result += Integer.toString(count)+",";

    }
    System.out.println(result.substring(0,result.length()-1));
}

Answer 5

The solution using Array.join , Array.sort and String.split functions:

var arr = ["max","mona"],
    counts = {};

arr = arr.join("").split(""); // transforms the initial array into array of single characters
arr.sort();
arr.forEach((v) => (counts[v] = (counts[v])? ++counts[v] : 1));

console.log(counts);  // {a: 2, m: 2, n: 1, o: 1, x: 1}

Answer 6

Try this:

var words = ['max', 'mona'],
    output = {};
    words.forEach(function(word){ 
    for(i=0; i < word.split('').length; i++){
    if(output[word[i]])
      output[word[i]] += 1;
    else{
      output[word[i]] = 1;
    }  
  } 
});

ps: sorry for the code not being formatted, I'm still getting used to the editor =)