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如何从gulp:watch忽略node_modules目录?

[英]How to ignore node_modules directory from gulp:watch?

I have a gulp script that watches for code changes in all javascript files . 我有一个gulp脚本,监视所有javascript files代码更改。 It looks like this: 看起来像这样:

gulp.watch(['./**/*.jsx', './**/*.js'], ['build:react']);

So, it watches for all .js and .jsx files from root directory, but I want to ignore node_modules directory. 因此,它从根目录中.jsx所有.js.jsx文件,但我想忽略node_modules目录。 How can I do that ? 我怎样才能做到这一点 ?

You ca use gulp unwatch This removes the folder specified from your pipe. 您可以使用gulp unwatch这将从管道中删除指定的文件夹。 However, it's generally a good idea to have a source folder that gulp watches instead of the project root folder (then the .git directory and all sorts will be caught up in your task. 但是,通常最好有一个gulp监视的source文件夹,而不是项目根文件夹(然后, .git目录和所有各种内容都将落入您的任务中。

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