如何从列表中的项目中删除标点符号并将其另存为列表中的单独项目？

Question

I am trying to compress items from one list to another list and I need to be able to save punctuation as separate items in the list because if I don't, "you" and "you;" are saved as separate items in the list.

For example the original list is,

['Ask', 'not', 'what', 'your', 'country', 'can', 'do', 'for', 'you;', 'ask', 'what', 'you', 'can', 'do', 'for', 'your', 'country!', 'This', 'is', 'a', 'quote', 'from', 'JFK', 'who', 'is', 'a', 'former', 'American', 'President.']

and the compressed list is currently,

['Ask', 'not', 'what', 'your', 'country', 'can', 'do', 'for', 'you;', 'ask', 'you', 'country!', 'This', 'is', 'a', 'quote', 'from', 'JFK', 'who', 'former', 'American', 'President.']

but I want it to have punctuation as separate items in the list.

My intended output is,

['Ask', 'not', 'what', 'your', 'country', 'can', 'do', 'for', 'you', ';', 'ask', '!', 'This', 'is', 'a', 'quote', 'from', 'JFK', 'who', 'former', 'American', 'President', '.']

Answer 1

You can implement with regex .

import re
a = ['Ask', 'not', 'what', 'your', 'country', 'can', 'do', 'for', 'you;', 'ask', 'what', 'you', 'can', 'do', 'for', 'your', 'country!', 'This', 'is', 'a', 'quote', 'from', 'JFK', 'who', 'is', 'a', 'former', 'American', 'President.']
result = re.findall(r"[\w']+|[.,!?;]",' '.join(a))

Output

['Ask', 'not', 'what', 'your', 'country', 'can', 'do', 'for', 'you', ';', 'ask', 'what', 'you', 'can', 'do', 'for', 'your', 'country', '!', 'This', 'is', 'a', 'quote', 'from', 'JFK', 'who', 'is', 'a', 'former', 'American', 'President', '.']

Here is a demo to understand more about regex .

Answer 2

This is the code to separete the non alphabetic characters and also remove duplicates. hope it helps.

def separate(mylist):
    newlist = [] 
    test = ''
    a = ''
    for e in mylist:
        for c in e:   
            if not c.isalpha():
                a = c
            else:
                test = test + c
        if a != '':
            newlist = newlist + [test] + [a]
        else:
            newlist = newlist + [test]
        test = ''
        a = ''
    noduplicates = []
    for i in newlist:
        if i not in noduplicates:
            noduplicates = noduplicates + [i]
    return noduplicates

I`m sure someone else can do better couse this is a bit messy but at least works.