在mysql ..中，如何获取时差大于1小时的上下数据？

Question

I have a table having per hour table records like this :

As you can see every record have 1 hour difference but the highlighted one has more than one hour. I need a query which should return me both values upper ( id 11379728 ) and lower ( id 11378448 ) where gap is more than 1 hour.

Any help will be appreciated.

Note :- please ignore last datetime column as it serves different purpose.

Answer 1

I got a working solution (perfect in my case) :

SET @lastDate := (SELECT dateColumn FROM table ORDER BY dateColumn ASC LIMIT 1);

SELECT @lastDate as lastDate, HOUR(TIMEDIFF(dateColumn, @lastDate)) as diff, @lastDate := dateColumn, dateColumn
FROM table 
group by dateColumn 
having diff > 1
order by dateColumn ASC;

In some cases mysql 5.5 and 5.6 will give different results for HAVING clause. Above query will run good on mysql 5.5. I have created another version to run on both version similarly like this :

SET @lastDate := (SELECT dateColumn FROM table ORDER BY dateColumn ASC LIMIT 1);

SELECT * FROM (SELECT @lastDate as lastDate, HOUR(TIMEDIFF(dateColumn, @lastDate)) AS diff, @lastDate := dateColumn, dateColumn FROM table GROUP BY dateColumn ORDER BY dateColumn ASC) AS tbl  WHERE tbl.diff > 1;