从pandas和python中的csv列复制一系列文本

Question

I have a csv file that I have imported into Pandas. Now it has almost 45 columns of data and each column has more than 100 lines of information. Now I need to select only the range of text that starts with a Date Stamp at the start and ends with a Date Stamp.

Ex :

<GMT2015-09-01 00:03:29GMT> Hi Rajiv<GMT2015-09-01 19:08:15GMT> Hi Ram <GMT2015-09-01 19:08:15GMT>

So, in such structure I need to select only the first paragraph of datestamp to datestamp into a new data frame.

Answer 1

I think you can split data in column Ticket Description by <> and then select output DataFrame by iloc . Last you can strip starts and ends whitespaces.

Notice: It works nice if <> are only in start and end od each datetime.

import pandas as pd

df = pd.DataFrame({'Ticket Description':['<GMT2015-09-01 00:03:29GMT> Hi Rajiv<GMT2015-09-01 19:08:15GMT> Hi Ram <GMT2015-09-01 19:08:15GMT> ']})
print (df)
                                  Ticket Description
0  <GMT2015-09-01 00:03:29GMT> Hi Rajiv<GMT2015-0...

print (df['Ticket Description'].str.split(r'[<>]', expand=True).iloc[:, 2].str.strip())
0    Hi Rajiv
Name: 2, dtype: object

Answer 2

Regex and pandas apply should achieve what you want. I'm assuming u want only the text between the very first and second timestamp. I have created a dataframe with your message, except the second one starts with 2. >(.+?)< in the regex searches for the any number of characters surrounded by a > and < . The ? makes it non greedy so it doesnt go from the first timestamp all the way to the last and stops at the first match.

Sample code below:

import pandas as pd
import re

data = pd.DataFrame({"id":[1,2],"ticket_desc":[r"<GMT2015-09-01 00:03:29GMT> Hi Rajiv, As part of our job Request for your approval. Thanks <GMT2015-09-01 19:08:15GMT> Hi Ram, Request Approved Thanks <GMT2015-09-01 19:08:15GMT>.",r"<GMT2015-09-01 00:03:29GMT> 2Hi Rajiv, As part of our job Request for your approval. Thanks <GMT2015-09-01 19:08:15GMT> Hi Ram, Request Approved Thanks <GMT2015-09-01 19:08:15GMT>."]})
def finder(x):
    return re.findall(">(.+?)<",x)[0]
data["ticket_desc"] = data["ticket_desc"].apply(finder)
print data["ticket_desc"][0]
print data["ticket_desc"][1]

Output:

Hi Rajiv, As part of our job Request for your approval. Thanks 


 2Hi Rajiv, As part of our job Request for your approval. Thanks