[英]How to write SQL query for following scenario
I have a table in following structure. 我有一个以下结构的表格。
Group Member/Owner Type
G1 M1 Member
G1 OW1 Owner
G2 OW1 Owner
G3 OW1 Owner
G3 OW2 Owner
G4 M2 Member
G4 OW2 Owner
Now, I want to query all Groups that has only Owner and do not have a single member. 现在,我想查询只有所有者且没有单个成员的所有组。
The required query should return the groups G2 and G3 for above table since it has only owners and not a single member. 所需的查询应返回上表的组G2和G3 ,因为它只有所有者而不是单个成员。
Can anyone help me to achieve this? 任何人都可以帮我实现这个目标吗?
You can do this with aggregation and having
: 您可以通过聚合执行此操作并having
:
select [group]
from t
group by [group]
having min(type) = 'Owner' and max(type) = 'Owner';
This says that the minimum and maximum value of type
is 'Owner'
-- which means that the value is always 'Owner'
(or possibly NULL
). 这表示type
的最小值和最大值是'Owner'
- 这意味着该值始终为'Owner'
(或可能为NULL
)。
Alternatively, you can express the having
clause as: 或者,您可以将having
子句表示为:
having sum(case when type = 'Member' then 1 else 0 end) = 0
Select [group] from
(
Select [group],
sum( case when type='member' then 1 else 0 end) as cntmember,
sum( case when type='owner' then 1 else 0 end) as cntowner
from tab group by [group]) tab
where cntmember=0 and cntowner=1
Using Left Outer Join: 使用左外连接:
SELECT G1 FROM
(SELECT GROUPS G1, TYPE T1 FROM temp
WHERE TYPE = 'Owner') TAB1
LEFT JOIN
(SELECT GROUPS G2, TYPE T2 FROM temp
WHERE TYPE = 'Member') TAB2
ON TAB1.G1 = TAB2.G2
WHERE T2 IS NULL
GROUP BY G1;
declare @Table1 TABLE
(Groups varchar(2), Owner varchar(3), Type varchar(6))
;
INSERT INTO @Table1
(Groups, Owner, Type)
VALUES
('G1', 'M1', 'Member'),
('G1', 'OW1', 'Owner'),
('G2', 'OW1', 'Owner'),
('G3', 'OW1', 'Owner'),
('G3', 'OW2', 'Owner'),
('G4', 'M2', 'Member'),
('G4', 'OW2', 'Owner')
;
;WITH CTE AS (
Select T.Groups,T.Type,T.Owner from (
select Groups, Owner, Type,ROW_NUMBER()OVER(PARTITION BY Groups ORDER BY Type)RN from @Table1
)T WHERE T.RN = 1 AND T.Type <> 'member')
Select * from @Table1 T WHERE EXISTS (Select 1 from CTE WHERE Groups = T.Groups)
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