提取特定字符之间的子字符串

Question

I have some strings like:

\i{}Agrostis\i0{} <L.>

I would like to get rid of the '\\i{}', '\\io{}' characters, so that I could get just:

Agrostis <L.>

I've tried the following code (adapted from here ):

m = re.search('\i{}(.+?)\i0', item_name)
if m:
   name = m.group(1).strip('\\')
else:
   name = item_name

It works in part, because when I run it I get just:

Agrostis

without the

<L.>

part (which I want to keep).

Any hints?

Thanks in advance for any assistance you can provide!

Answer 1

使用s.replace('\\i{}', '')和s.replace('\\io{}', '')

Answer 2

You ca do this in different ways.

The simplest one is to use str.replace

s = '''\i{}Agrostis\i0{} <L.>'''
s2 = s.replace('''\i{}''', '').replace('''\i0{}''', '')

Another way is to use re.sub()

Answer 3

You need to use the re.sub function.

In [34]: import re

In [35]: s = "\i{}Agrostis\i0{} <L.>"

In [36]: re.sub(r'\\i\d*{}', '', s)
Out[36]: 'Agrostis <L.>'

Answer 4

You could use a character class along with re.sub()

import re
regex = r'\\i[\d{}]+'
string = "\i{}Agrostis\i0{} <L.>"

string = re.sub(regex, '', string)
print string

See a demo on ideone.com .

Answer 5

You can either use s.replace('\\i{}', '') and s.replace('\\io{}', '') , as Julien said, or, continuing with the regex approach, change your pattern to:

re.search('\\i{}(.+?)\\i0(.++)', item_name)

And use m.group(1).strip('\\\\') + m.group(2).strip('\\\\') as the result.