[英]How to dial a number
I am trying to dial a number like *123*0xxxxxxxxxx# . 我想拨打* 123 * 0xxxxxxxxxx#这样的号码。 And the 0xxxxxxxxxx portion would be got from the user input through an edit text.my code is here
并且0xxxxxxxxxx部分将通过编辑文本从用户输入获得。我的代码在这里
EditText et1;
String ET1;
String pnd,encode_zero;
Button call;
Intent callIntent = new Intent(Intent.ACTION_CALL);
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.call);
et1 = (EditText) findViewById(R.id.et1);
call = (Button) findViewById(R.id.btn_call);
ET1 = et1.getText().toString();
call.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
pnd = Uri.encode("#");
encode_zero = Uri.encode("0");
callIntent.setData(Uri.parse("tel:*123*0" + ET1 + pnd));
startActivity(callIntent);
}
});
but when I run the app it ends with telling invalid number . 但是当我运行应用程序时,它会告诉无效的号码。 that means I think the zero(0) is not considered.
这意味着我认为不考虑零(0)。 I have tried with this one too...
我也尝试过这个......
public void onClick(View v) {
pnd = Uri.encode("#");
encode_zero = Uri.encode("0");
callIntent.setData(Uri.parse("tel:*123*" + encode_zero + ET1 + pnd));
startActivity(callIntent);
}
but the result is all the same. 但结果都是一样的。 Now what can I do ?
现在我该怎么办?
确保将此权限添加到清单
<uses-permission android:name="android.permission.CALL_PHONE" />
This code opens the phone dialer with the number on it - 此代码打开带有号码的电话拨号器 -
String number = "*123*0123456#";
Intent callIntent = new Intent(Intent.ACTION_CALL);
callIntent.setData(Uri.parse("tel:" + Uri.encode(number)));
if (ActivityCompat.checkSelfPermission(getBaseContext(), Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
return;
}
startActivity(callIntent);
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