将数据存储在char *数组中

Question

My task is to store data in an array of char* in main(), and each row of the data being in its own string. I am suppose to hard-code the given data. Is this the right way to do it.

#include <stdio.h>

int main(void) {
    int i;

    char* numbers[5] {"12, 34, 56, 78",
                      "82.16, 41.296",
         "2, -3, 5, -7, 11, -13, 17, -19",
        "9.00009, 90.0009, 900.009, 9000.09, 90000.9"};
    for(i=0;i<5;i++){
    //print//
    }


}

Answer 1

char* numbers[5] {"12, 34, 56, 78",
                  "82.16, 41.296",
                  "2, -3, 5, -7, 11, -13, 17, -19",
                  "9.00009, 90.0009, 900.009, 9000.09, 90000.9"};

You forget the =

And there are only 4 strings in your array, change to

char *numbers[] = {"12, 34, 56, 78",
                   "82.16, 41.296",
                   "2, -3, 5, -7, 11, -13, 17, -19",
                   "9.00009, 90.0009, 900.009, 9000.09, 90000.9"};

And here

for(i=0;i<5;i++){

Don't use magic numbers like 5 , instead, use the sizeof operator in order to get the correct size:

for (i = 0; i < (sizeof numbers / sizeof *numbers); i++){