检查文件是否存在于regex Linux指定的目录中

Question

I'm trying to use regex inside a file operator to seek for a file where one subdirectory is specified with a regex, but I wonder if it's even possible. I think I tried all the quote and bracket combinations possible. Either I'm missing something here, or a file operator requires a specific path?

I'm not entirely sure. Could somebody please clarify?

What I want to achieve is something like this (this obviously doesn't work because it takes the regex part as name of the subdirectory)

if [[ -r '/agent/[0-9 .]*/bin/run.sh' ]]

Answer 1

find has a -regex option

-regex pattern

File name matches regular expression pattern. This is a match on the whole path, not a search. For example, to match a file named ./fubar3', you can use the regular expression .*bar.' or .*b.*3 , but not f.*r3 . The regular expressions understood by find are by default Emacs Regular Expressions, but this can be changed with the -regextype option.

if find . -regex '/agent/[0-9 \.]*/bin/run.sh'

Answer 2

According to the manual , only the =~ operator does regex matching.

There's another way though:

RUNFILES=$( find /agent -name run.sh | grep -e '^/agent/[0-9 .]*/bin/run.sh$' )
if [ -n "$RUNFILES" ]
then
[...]
fi

Answer 3

您可以简单地使用ls命令和正则表达式：

if ls /agent/[0-9\ .]*/bin/run.sh