在最近出现的子字符串中分割字符串

Question

I need help to split string when substring is found, only on latest occurrence

 Substring to search(example):123 
 String: 123hello123boy123guy123girl 
 Res: 123hello123boy123guy (result on split[0])

 Ex: hello123boy
 Res:hello 

I'm trying with this function, but this split only on first occource.

public static String[] getSplitArray(String toSplitString, String spltiChar) {
    return toSplitString.split("(?<=" + spltiChar + ")");
    }

Answer 1

If you want to do it in single split() , this should work:

string.split("123((?!123).)*?$")

Eg:

String s = "foo123bar123hhh123tillHere123Bang";
System.out.println(s.split("123((?!123).)*?$")[0]);

Outputs:

foo123bar123hhh123tillHere

Another approach would be, just split("123") then join the elements you required by 123 as delimiter.

Answer 2

You don't need a regex for that, you can simply use String#lastIndexOf :

-> String s = "123hello123boy123guy123girl"

-> s.substring(0, s.lastIndexOf("123"));
|  Expression value is: "123hello123boy123guy"

-> s.substring(s.lastIndexOf("123"));
|  Expression value is: "123girl"

Answer 3

Improvement on Kent 's answer: this will actually give you a split array rather than a single-element array with the first part of your String :

String[] text = {
        "123hello123boy123guy123girl", // 123hello123boy123guy 
        "hello123boy"// hello
};
for (String s: text) {
    System.out.println(
        Arrays.toString(
            s.split("123(?=((?!123).)*?$)")
        )
    );
}

Output

[123hello123boy123guy, girl]
[hello, boy]