如何在批处理程序中打开文件？

Question

I want to open a file that is in a directory down ( folder/file.bat ) but i want to open it in Notepad++ not cmd.exe. And i want to do this without changing the default program.

How would i do this in batch

I've tried this:

start "" "C:\Program Files (x86)\Notepad++\notepad++.exe" -%server%\run.bat

But it doesn't work.

Answer 1

I didnt exactly understand your question. But from what I understood I tried the following.

For me I just tried simply putting the filename as an argument to notepad++.exe In my example I kept the file in D:\\Test\\Notepad++.bat and the Test file Test.txt in D:\\Test.txt I wrote this command and it works for me

start "" "C:\Program Files\Notepad++\notepad++.exe" ..\Test.txt

Hope it helps

The link here shows the command line arguments which can be passed to notpad++.exe