[英]java testTimer to test execution time
I have a function which checks the satiability of a logic expression also it shows the checking time. 我有一个检查逻辑表达式是否令人满意的函数,它还显示了检查时间。 I put an input example and it shows that it takes about 10000 milliseconds(10 sec) to run but why when I try to remove all the code lines associated with the testTimer it only took less than a second to run the code with the same input?
我放了一个输入示例,它显示运行大约需要10000毫秒(10秒),但是为什么当我尝试删除与testTimer相关的所有代码行时,只用不到一秒钟的时间就可以运行具有相同输入的代码?
protected boolean runSat() {
testTimer.start();
boolean result = checkSatisfiability();
testTimer.stop();
 options.getLog().print("\nChecking time was ", testTimer.getResultTim e()," milliseconds");
testTimer.reset();
finaliseStatistic();
if (result) {cGraph.print(options.getLog());}return result;}
 
The original code is available here: http://grepcode.com/file/repo1.maven.org/maven2/net.sourceforge.owlapi/jfact/1.0.0/uk/ac/manchester/cs/jfact/kernel/DlSatTester.java 原始代码位于此处: http : //grepcode.com/file/repo1.maven.org/maven2/net.sourceforge.owlapi/jfact/1.0.0/uk/ac/manchester/cs/jfact/kernel/DlSatTester .java
protected boolean runSat() {
long startTime = System.nanoTime();
boolean result = checkSatisfiability();
long endTime = System.nanoTime();
 options.getLog().print("\nChecking time was ", (endTime - startTime)/1000000," milliseconds");
testTimer.reset();
finaliseStatistic();
if (result) {cGraph.print(options.getLog());}return result;}
You could try if this is faster (if that was what you were asking) 您可以尝试这样是否更快(如果那是您要的)
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