我的C程序中运行时错误的原因＆？

Question

        #include<stdio.h>
        main()
        {char *names[4];
        int i,a;
        printf("ënter the guests names\n");
               for(i=0;i<=3;i++)
               {
                 scanf("%s",names[i]);
               }
      char *yourname;
      printf("\nenter your name ");
      scanf("%c",yourname);
                    for(i=0;i<=3;i++)
                       {a=strcmp(names[i],yourname);
                         if(a==0)
                         printf("\nwelcome");
                         break;
                       }
     if(a!=0)
     printf("\naccess denied");
     return 0;
     }

this is a program to check your entry in a show. first we give permitted names & then it asks your name ,it compares your name with the names in the guest list.

im getting runtime error, plz tell me the correction.i want to use pointers to string so plz suggest correction in the existing program

when i run this program in devc++ after entering first name it gives program.exe stopped working.

Answer 1

The code will be like this:

    #include <stdio.h>
    #include <string.h>
    #include <stdlib.h>

    int main()
    {
        char *names[4];
        int i,a;
        printf("ënter the guests names\n");
        for(i=0;i<=3;i++) {
                names[i] = (char*) malloc(100 * sizeof(char));
            scanf("%s", names[i]);
        }
        char yourname[100];
        printf("\nenter your name ");
        scanf("%s",yourname);
        for(i=0;i<=3;i++) {
            a = strcmp(names[i], yourname);
            if (a == 0) break;
        }
        if (a==0)
            printf("\nwelcome");
        else printf("\naccess denied");

        for(i=0;i<=3;i++)
            free(names[i]);

        return 0;
    }

Answer 2

Your code have to be formated so we can give you a better answer.

Now, use gets to take your input, verify the guest match with your name inside the for loop, stop the loop when a match is found.

#include<stdio.h>
#include<string.h>
int main()
{
    char names[4][20];
    int i = 0;
    int a = 0;
    printf("Enter guests names: \n");

    for(i=0; i<3; i++)
    {
        gets(names[i]);
    }
    char yourname[20];
    printf("\n Enter your name ");
    gets(yourname);

    printf("\n Verify access right:");
    for(i=0; i<3; i++)
    {    
        a=strcmp(names[i], yourname);
        if(a==0)
        {
            printf("\n welcome");
            break;
        }
        else
        {
            printf("\n access denied");
        }
    }  

    return 0;
}

Although this looks like a homework assignment.