Yii2 同一模型的多个实例与 javascript

Question

I am trying to use multiple instances of the same model using javascript append. However, I do not know how to do that. Therefore, I create the following code.

javascript

var div_input = $('#input');
div_input.append('<input type="hidden" name="'+c+'_round" value="'+c+'" />');

variable "c" is a increasing running number. for example, first time i append the name will be "1_round". and second time will be "2_round" and so on.

Controller

 $loop = true;
    $i = 0;
    do{
        $i++;
        if (!empty($_POST[$i . "_round"]))
        {
            $round = $_POST[$i . "_round"];
            $model->model_round= $round;
            $model->save();
        }else{
            $loop = false;
        }
    }while($loop);

The problem here is it will always only save the last loop of data and not every loop of data. Please help me with this. New to Yii2. Thanks!

Answer 1

You have to initialize new instance of $model each time in loop

ie

    $saved_array = [];
    $loop = true;
    $i = 0;
    do{
        $i++;
        if (!empty($_POST[$i . "_round"]))
        {
            $model = new model();
            $round = $_POST[$i . "_round"];
            $model->model_round= $round;
            if($model->save()) {
                $saved_array[$model->id] = True;
            } else {
                $saved_array[$model->id] = $model->getErrors();
            }
            unset ($model);
        }else{
            $loop = false;
        }
    }while($loop);

You can finally analyize if model is saved or not if not saved what are the errors with the $saved_array

Answer 2

Why don't you use input name as array

<input name="round[]">

Then loop it

$round = $_POST['round'];
foreach( $round as $key => $n ) {
// code here
}