Laravel 5.2：如何在没有php标签的刀片模板中设置变量？

Question

I can define a variable using below in blade

<?php $var = var1 - var2; ?>

and then print it as

{{ $var }}

but how to set a variable using laravel blade template method and then use it, basically @set alternative in 5.2?

Answer 1

There is this package for laravel 4 but it's not compatible with laravel5 due to it's composer file. A quick pull request would fix that.

The main part of the package is only three lines which could be added to your AppServiceProvider 's boot method if you didn't want to pull in a package for it:

\Blade::extend(function($value, $compiler) {
    $value = preg_replace("/@set\('(.*?)'\,(.*)\)/", '<?php $$1 = $2; ?>', $value); 
    return $value;
});

Here's some examples from the readme.

@set('my_variable', $existing_variable)

You can then use the variable $my_variable in the template.

---

You might choose to fetch a bunch of models from your template, for example

@set('my_model_list', MyModel::where('something', '=', 1)->paginate(10))

Answer 2

You can use blade comment syntax

{{--*/ $var = $var1 - $var2; /*--}}
{{ $var }}

Code above will be translated to following snippet

<?php /**/ $var = $var1 - $var2; /**/ ?>

Read more: http://laravel-recipes.com/recipes/256/assigning-a-variable-in-a-blade-template

Answer 3

Try this,

@if($var=$var1-$var2)@endif

and print,

{{ $var }}