在KeyboardInterrupt（）上捕获回溯

Question

I have a code that I use to stop on Ctrl+C. I would like to do some things juste after i did Ctrl+C. Therefore I write:

try:
    work()
except KeyboardInterrupt:
    do_other_stuff()

But I don't see where I did Ctrl+C, as no Traceback prints; I want to see the usual message

    Traceback (most recent call last):
       File "X.py", line 16, in <module>
         ...

How can I print this? I tried to do

    except KeyboardInterrupt as e:
       print str(e)
       do_other_stuff()

but it prints nothing.

Answer 1

import sys, traceback
def func():
    try:
        work()
    except KeyboardInterrupt:
        do_something()
        traceback.print_exc(file=sys.stdout)

if file is omitted then the output goes to stderr . for more on traceback... https://docs.python.org/2/library/traceback.html

Answer 2

KeyboardInterrupt继承自BaseException ，在BaseException您可以使用traceback.format_exc(e)获得错误所在的行。

Answer 3

You were close:

try:
    while True:
        x = 1
except KeyboardInterrupt as e:
    print 'Here we are, in the error handler!'
    raise e

Just make sure you run do_other_stuff() before you call raise e .