将带有附加参数的curl转换为PHP curl

Question

Trying to convert a curl command for building Jenkins job so I can use it in PHP. Here is what I do:

<?php

        $testrun_id = "1744";
        $cmd="curl -X POST http://build:f9280f220bfb4c596f83a0@mobile-jenkins.me.com:8080/job/android-job-git/build --data-urlencode json='{"parameter": [{"name":"POST_RESULTS", "value":"true"}, {"name":"RUN_ID", "value":"{$testrun_id}"}, {"name":"CHECK_NAME", "value":"SampleAutomatedPlan"}]}'";
        exec($cmd, $result);

?>

Here I am passing 3 parameters to the jenkins job and they are POST_RESULTS with value true , RUN_ID with value of var $testrun_id which is 1744 and CHECK_NAME whose value is SamplAutomatedPlan . When I run this curl command on mac terminal, it works perfectly fine.

What would be the missing things OR errors that gives me Parse error: parse error on that $cmd="curl..." line when I try to run this php script?

Answer 1

您需要通过添加反斜杠来转义双引号。

$cmd = "curl -X POST http://build:f9280f220bfb4c596f83a0@mobile-jenkins.me.com:8080/job/android-job-git/build --data-urlencode  json='{\"parameter\": [{\"name\":\"POST_RESULTS\", \"value\":\"true\"}, {\"name\":\"RUN_ID\", \"value\":\"{$testrun_id}\"}, {\"name\":\"CHECK_NAME\", \"value\":\"SampleAutomatedPlan\"}]}'";