如何将异步调用转换为同步？

Question

I'm pretty new to RxJava and I would like to make a method call, that returns an Observable, sync.

This is the method signature:

JsonObject login();

I tried something like this, but it didn't work:

public JsonObject login() {
    return eventBus
    .sendObservable(...)
    .toBlocking().first().body();
}

How can I make it work?

Thank you.

Answer 1

Observable by design is Synchronous, if you want any operation Asynchronous you must use one of the specific operators.(onSubscribe, onObserver, buffer....)

Also don't use toBlocking unless for your test, is almost an anti pattern, try to use the Observer pattern instead.

     public void main(String args[]){

         login().subscribe(jsonObject-> do Whatever you need);
     }


     public Observable<JsonObject> login() {
        return eventBus.sendObservable(...) --> I guess this call return an Observable
     }

If you want to take a look some basic examples take a look here https://github.com/politrons/reactive