正则表达式接受-字符
[英]Regular Expression to accept - character
问题描述
I currently have a regular expression to validate a field within my application which looks like this: 
我目前有一个正则表达式来验证我的应用程序中的字段，如下所示：
^(?:(?:\\w|[-])+\\.(?:(?:(?:\\w|[-])+|\\.))*(?:\\/(?:\\w|[-])*)*|\\w*)$
Unfortunately some aspects of this does not work. 不幸的是，这在某些方面是行不通的。
aaa - Passes - Correct
aaa-通过- 正确 aaa.aaa - Passes - Correct
aaa.aaa-通过- 正确 aaa.aaa-aaa - Passes - Correct
aaa.aaa-aaa-通过- 正确 aaa-aaa - Fails - Incorrect
aaa-aaa-失败- 不正确
How am I able to change my regular expression in order to make the last scenario pass? 我如何更改正则表达式以使最后一个场景通过？
1 个解决方案
解决方案1
1 已采纳 2016-07-04 07:54:58
The first \\. 第一\\. causes your last expression to fail. 导致您的最后一个表达式失败。 Since there are more groups, the first part of your expression has to match. 由于存在更多的组，因此表达式的第一部分必须匹配。
If you make the dot optional, your expression works. 如果将点设为可选，则表达式有效。
Not sure, but maybe you can simplify the expression like this: 不确定，但是也许您可以像这样简化表达式：
[A-Za-z]+([\-\.][A-Za-z]+)*
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