有人可以为Scala的apache访问日志文件计算正则表达式吗？

Question

I am using the following regular expression in Scala

val Pattern = """^(\S+) (\S+) (\S+) \[([\w:/]+\s[+\-]\d{4})\] "(\S+) (\S+) (\S+)" (\d{3}) (\d+)""".r

val res = Pattern.findFirstMatchIn(logFile)

Yet it is giving me the following error:

: Cannot parse log line: 80-219-148-207.dclient.hispeed.ch - - [07/Mar/2004:19:47:36 -0800] "OPTIONS * HTTP/1.0" 200 -

Answer 1

The issue is that your regex expected the last parameter to be numeric ( \\d+ - one or more digits), but it came as a - (unknown, undefined). The previous subpatterns worked OK because \\S+ (1 or more non-whitespaces) matches a hyphen.

So, either replace the last \\d+ with \\S+ or use alternation (\\d+|-) . This latter approach can be extended to all the pattern parts like this:

^(\S+) (\S+) (\S+) \[([\w:/]+\s[+\-]\d{4})\] "(\S+) (\S+) (\S+)" (\d{3}|-) (\d+|-)
                                                                       ^^      ^^

See the regex demo .