Java - 从列表中分配正确的数字

Question

I have a non-repeated Shuffled list between 1 and 16 and a 2D array, What I'm trying to do is assing the number 16 to the position btn[3][3], all the other positions can have the other remaining list values (1 - 15)

Code:

int c = 0;
    int v = 0;
    for (int i=0; i<4; i++) {
        v=0;
        for(int j=0; j<4; j++){


            String number = Integer.toString(list.get(c));
            c++;

            if (i == 3 && j == 3){
                JButton btnmix = new JButton();
                btnBotonMix[i][j] = btnmix;
                btnBotonMix[i][j].setBounds(70+90*(i%10),v+90*(i/10),90,90);
                btnBotonMix[i][j].setText(number);
            }

            else{ 
                JButton btnmix = new JButton();
                btnBotonMix[i][j] = btnmix;
                btnBotonMix[i][j].setBounds(70+90*(i%10),v+90*(i/10),90,90);
                btnBotonMix[i][j].setText(number); 
            }

            v = v + 90;
        }
    }

What I'm looking for, is to always assign the number 16 in my index btn[3][3]

So I want get this (the number 16 always in [3][3] and all the remaining ones in a random position):

[0][0] 15
[0][1] 11
[0][2] 14
[0][3] 5
[1][0] 12
[1][1] 3
[1][2] 8
[1][3] 9
[2][0] 6
[2][1] 2
[2][2] 13
[2][3] 1
[3][0] 4
[3][1] 7
[3][2] 10
[3][3] 16

Answer 1

    // always put 16 last
    final int lastNumber = 16;
    // take it out from the list from the start
    list.remove(Integer.valueOf(lastNumber));
    for (int i = 0; i < 4; i++) {
        v = 0;
        for (int j = 0; j < 4; j++) {

            String number;
            if (i == 3 && j == 3) {
                number = Integer.toString(lastNumber);
            } else {
                number = Integer.toString(list.get(c));
                c++;
            }

            JButton btnmix = new JButton();
            btnBotonMix[i][j] = btnmix;
            btnBotonMix[i][j].setBounds(70 + 90 * (i % 10), v + 90 * (i / 10), 90, 90);
            btnBotonMix[i][j].setText(number);

            v = v + 90;
        }
    }

Answer 2

Please try this and let me know -

int c = 0;
int v = 0;
Arrays.sort(list);//added
for (int i = 0; i < 4; i++) {
    v = 0;
    for (int j = 0; j < 4; j++) {
        String number = Integer.toString(list.get(c)); //Changed
        c++;
        if (i == 3 && j == 3) {
            JButton btnmix = new JButton();
            btnBotonMix[i][j] = btnmix;
            btnBotonMix[i][j].setBounds(70+90*(i%10),v+90*(i/10),90,90);
            btnBotonMix[i][j].setText(number);
        } else { 
            JButton btnmix = new JButton();
            btnBotonMix[i][j] = btnmix;
            btnBotonMix[i][j].setBounds(70+90*(i%10),v+90*(i/10),90,90);
            btnBotonMix[i][j].setText(number); 
        }
        v = v + 90;
    }
}

I do not think now you would need if else here.

Answer 3

The most simplest way is to check if the number retrieved is 16 when you reach the position [3][3]

    int c = 0;
    for (int i=0; i<a.length; i++) {
        for(int j=0; j<a.length; j++){
            String number = list.get(c);
            c++;
            JButton btnmix = new JButton();
            btnBotonMix[i][j] = btnmix;
            btnBotonMix[i][j].setBounds(70+90*(i%10),v+90*(i/10),90,90);
            if (i == 3 && j == 3){
                if(number.equals("16")){
                  btnBotonMix[i][j].setText(number); 
                }
            }
            else{ 
               btnBotonMix[i][j].setText(number); 
            }
        }
    }