我有一个具有两种不同日期值格式的csv文件，希望它们采用任何单一格式

Question

My CSV file looks like this

id       date
1602    11/23/2015 14:10
1602    11/23/2015 22:45
1602    18/10/2011 09:19:46 AM
1702    18/10/2011 09:07:33 AM
1863    18/10/2011 09:07:35 AM
1436    18/10/2011 09:07:36 AM

I'm looking for output like

id       date
1602    11/23/2015 14:10
1602    11/23/2015 22:45
1602    10/18/2011 09:19:46 AM
1702    10/18/2011 09:07:33 AM
1863    10/18/2011 09:07:35 AM
1436    10/18/2011 09:07:36 AM

Answer 1

I'm not sure why you are making this so much more difficult than it is. It seems that all you are actually doing is (1) getting rid of the first line of the CSV file; (2) tossing out any quotation marks; (3) mapping sets of spaces/tabs into single spaces; and (4) mapping newlines to spaces.

SO . . . how about the following? (I assume the data comes from standard input.)

sed 1d | tr -d /\\"/ | tr -s "/[ \\010\\012]/ /"

The 'sed' deletes the first line; the first 'tr' strips quotation marks; the second 'tr' maps runs of spaces, tabs, and/or newlines to single spaces (\\010 and \\012 are the octal codes for ASCII TAB and ASCII NL, respectively).