Windows-启动应用程序后使CMD.exe自动关闭

Question

File a.bat :-

start powershell "npm init"
code .

When I double click the above file, it opens a powershell window with the npm init command executed in it and it also opens visual studio code with current directory opened in it. cmd.exe exits after this. But for the following bat file:-

start /min powershell "gulp scss; gulp watch-scss;"
start /min powershell "gulp js; gulp watch-js;"
start /min powershell "http-server;"
code .

when I double click it, everything happens as it should except that cmd.exe does not exits and stays open in the waiting state (as it is waiting for visual studio code to close.)

How can I make cmd.exe to exit when all the commands have been executed (like in the case of a.bat )?

Update

The batch file does not keep cmd.exe opened if I omit the last line code . . The following batch file works perfectly fine:-

start /min powershell "gulp scss; gulp watch-scss;"
start /min powershell "gulp js; gulp watch-js;"
start /min powershell "http-server;"

The problem starts when I add the line code .

Answer 1

Try doing these

start "" /min powershell "gulp scss; gulp watch-scss;"
start "" /min powershell "gulp js; gulp watch-js;"
start "" /min powershell "http-server;"
code .

or if youre running a powershell file, use this

Powershell.exe -executionpolicy remotesigned -File  location\to\ps\file.ps