用json_encode转换（）
[英]converting with json_encode()
问题描述
<?php
$array = array("first elem", "second elem");
?>
<html>
<head>
</head>
<body>
<script>
var js_array = '<?php echo json_encode($array); ?>';
for (var i = 0; i < js_array.length; i++)
{
document.write(js_array[i]);
document.write("<br>");
}
</script>
</body>
I have PHP array with two elements, when I converting this array to javascript array with json_encode() javascript divide my PHP array into set of chars, so in javascript array in a result i have a lot of elements. 
我有两个元素的PHP数组，当我用json_encode()将这个数组转换为javascript数组时javascript将我的PHP数组分成一组字符，所以在javascript数组中我有很多元素。 How to convert PHP array with two elements to javascript array with the same two elements? 如何将具有两个元素的PHP数组转换为具有相同两个元素的javascript数组？
3 个解决方案
解决方案1
1 已采纳 2016-07-07 07:05:30
You php function json_encode will give you a valid object, that's in fact what it means, J ava S cript O bject N otation. 你的php函数json_encode将为你提供一个有效的对象，这实际上意味着什么， J ava S cript O bject N otation。
So by using it as it is you will create an object in your JavaScript code. 因此，通过使用它，您将在JavaScript代码中创建一个对象。 By enclosing it between apostrophes you are making it a string (who's value can be parsed as JSON). 通过将它放在撇号之间，你将它变成一个字符串（谁的值可以解析为JSON）。
So the simplest change would be to remove the apostrophes. 所以最简单的改变就是删除撇号。 So this line: 所以这一行：
var js_array = '<?php echo json_encode($array); ?>';
Should become 应该成为
var js_array = <?php echo json_encode($array); ?>;
解决方案2
1 2016-07-07 07:06:40
Replace you code with the following code.. 用以下代码替换代码..
<?php
$array = array("first elem", "second elem");
?>
<html>
<head>
</head>
<body>
<script>
var js_array = <?php echo json_encode($array); ?>;
for (var i = 0; i < js_array.length; i++)
{
document.write(js_array[i]);
document.write("<br>");
}
</script>
</body>
I hope its help you..... 我希望它对你有所帮助.....
解决方案3
1 2016-07-07 07:06:42
The problem is that you have enclosed the json_encode in colons so you are converting it to a string. 问题是您已将json_encode括在冒号中，因此您将其转换为字符串。 The javascript it produces is like this: 它产生的javascript是这样的：
var js_array = '["first elem","second elem"]';
Here js_array is an string but you want an array. 这里js_array是一个字符串，但你想要一个数组。 What you have to do is to produce the json directly as it will yield an array: 你要做的是直接生成json，因为它会生成一个数组：
var js_array = <?php echo json_encode($array); ?>;
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