[英]Template class as template parameter default parameter
Today I tried to pass a template class to a template parameter. 今天我尝试将模板类传递给模板参数。 My template class
std::map
has four template parameters, but the last two of them are default parameters. 我的模板类
std::map
有四个模板参数,但最后两个是默认参数。
I was able to get the following code to compile: 我能够得到以下代码来编译:
#include <map>
template<typename K, typename V, typename P, typename A,
template<typename Key, typename Value, typename Pr= P, typename All=A> typename C>
struct Map
{
C<K,V,P,A> key;
};
int main(int argc, char**args) {
// That is so annoying!!!
Map<std::string, int, std::less<std::string>, std::map<std::string, int>::allocator_type, std::map> t;
return 0;
}
Unfortunately, I don't want to pass the last two parameters all the time. 不幸的是,我不想一直传递最后两个参数。 That is really too much writing.
这真是太多了。 How can I use here some default template arguments?
我如何在这里使用一些默认模板参数?
You could use type template parameter pack (since C++11) to allow variadic template parameters: 您可以使用类型模板参数包 (从C ++ 11开始)来允许可变参数模板参数:
template<typename K, typename V,
template<typename Key, typename Value, typename ...> typename C>
struct Map
{
C<K,V> key; // the default value of template parameter Compare and Allocator of std::map will be used when C is specified as std::map
};
then 然后
Map<std::string, int, std::map> t;
Not ideal, but: 不理想,但是:
#include <map>
template<typename K, typename V, typename P,
typename A=typename std::map<K, V, P>::allocator_type,
template<typename Key, typename Value, typename Pr= P, typename All=A> typename C=std::map>
struct Map
{
C<K,V,P,A> key;
};
int main(int argc, char**args) {
Map<std::string, int, std::less<std::string>> t;
return 0;
}
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