Laravel 5.1 ajax简单URL路由显示未找到错误（404）

Question

<script type="text/javascript">
             function variants(master_id)
             {

              $.ajax({
                type: "GET",
                url: "getVariants"+'/'+master_id,
                success: function(){

              }
             });

             }
    </script>

This is the script that I have defined and kept is as simple as possible.

The route is this and it still shows me 404 not found error.

Route::get('getVariants/{master_id}','Retailer\ProductController@getVariants');

Answer 1

将完整的网址路径http://example.com/getVariants/master_id添加到ajax调用

Answer 2

<meta name="_token" content="{{ csrf_token() }}"/>
headers: {'X-CSRF-TOKEN': $('meta[name="_token"]').attr('content')}

Answer 3

尝试

url: "/getVariants"+'/'+master_id,

Answer 4

尝试以下方法：

Route::any('getVariants/{master_id}','Retailer\ProductController@getVariants');