如何使Django url正则表达式不包含所有单词？

Question

This is my project's url patterns :

urlpatterns = [
    # ex) /snu/
    url(r'^$', views.site_list, name='site_list'),

    # ex) /snu/cse/
    url(r'^(?i)(?P<site_name>[a-zA-Z]+)/$', views.post_list, name='post_list'),

    # ex) /snu/cse/post/3
    url(r'^(?i)(?P<site_name>[a-zA-Z]+)/post/(?P<pk>[0-9]+)/$', views.post_detail, name='post_detail'),

    # ex) /snu/cse/post/3/remove
    url(r'^(?i)(?P<site_name>[a-zA-Z]+)/post/(?P<pk>\d+)/remove/$', views.post_remove, name='post_remove'),

    # ex) /snu/upload
    url(r'^(?i)upload/$', views.upload, name='upload'),
]

Unfortunately, r'^(?i)(?P<site_name>[a-zA-Z]+)/$' catches everything so /snu/upload doesn't work as I expected.

Something like r'^(?i)(?P<site_name>[a-zA-Z]+)/upload$' might works, but I don't want it. It should be r'^(?i)upload/$' . Any ideas?

Answer 1

The order matters in pattern matching for URL dispatcher. The first match is resolved and returned.

Django runs through each URL pattern, in order, and stops at the first one that matches the requested URL.

So you might want to move the "specific" patterns higher up.

In other words, move

# ex) /snu/upload
url(r'^(?i)upload/$', views.upload, name='upload'),

to the second position.

• Documentation can be found here