CSV文件到Python列表中

Question

I have a csv file (named "test.csv") containing this list with tuples:

[('calculation', 1468171987.4406562, None), ('calculation', 1468171988.5840397, None), ('calculation', 1468171989.8159678, 1.9041595458984375)]5)]

How can I import this csv file and save its contents to a list like this:

record = []

after the import

record = [('calculation', 1468171987.4406562, None), ('calculation', 1468171988.5840397, None), ('calculation', 1468171989.8159678, 1.9041595458984375)]

This is what I tried:

import csv
    with open ("test.csv", 'rb') as f:
        reader = csv.reader(f)
        record = reader

Attempt 2:

import csv

with open ("test.csv", 'rb') as f:
    reader = csv.reader(f)
    record = list(reader)

Then I get this error:

_csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)

Answer 1

Now that you have a CSV reader (I assume your real code is indented correctly and runs without syntax error), you need to use it to input the lines from the file. The simplest way is like this:

record = list(reader)

Answer 2

You can use ast.literal_eval

import ast
with open ("test.csv", 'r') as f:
    for line in f:
        list = ast.literal_eval(line)
        print list