使用函子（Scalaz7）提升采用隐式参数的函数

Question

Just started learning Scalaz. Here is my code

trait Monoid[A] {
     def mappend(a1: A, a2: A): A
     def mzero: A
}

object Monoid {
    implicit val IntMonoid: Monoid[Int] = new Monoid[Int] {
        def mappend(a1: Int, a2: Int): Int = a1 + a2
        def mzero: Int = 0
    }

    implicit val StringMonoid: Monoid[String] = new Monoid[String] {
        def mappend(a1: String, a2: String): String = a1 + a2
        def mzero: String = ""
    }
}

trait MonoidOp[A] {
    val F: Monoid[A]
    val value: A
    def |+|(a2: A): A = F.mappend(value, a2)
}

object MonoidOp{
    implicit def toMonoidOp[A: Monoid](a: A): MonoidOp[A] = new MonoidOp[A]{
        val F = implicitly[Monoid[A]]
        val value = a
    }
}

I have defined a function (just for the sake of it)

def addXY[A: Monoid](x: A, y: A): A = x |+| y

I want to lift it so that it could be used using Containers like Option, List, etc. But when I do this

def addXYOptioned = Functor[Option].lift(addXY)

It says error: could not find implicit value for evidence parameter of type scalaz.Monoid[A] def addOptioned = Functor[Option].lift(addXY)

How to lift such functions?

Answer 1

Your method addXY needs a Monoid[A] but there is no Monoid[A] in scope when used in addXYOptioned , so you also need to add the Monoid constraint to addXYOptioned .

The next problem is that Functor.lift only lifts a function A => B , but we can use Apply.lift2 to lift a function (A, B) => C .

Using the Monoid from Scalaz itself :

import scalaz._, Scalaz._

def addXY[A: Monoid](x: A, y: A): A = x |+| y

def addXYOptioned[A: Monoid] = Apply[Option].lift2(addXY[A] _)

We could generalize addXYOptioned to make it possible to lift addXY into any type constructor with an Apply instance :

def addXYApply[F[_]: Apply, A: Monoid] = Apply[F].lift2(addXY[A] _)

addXYApply[List, Int].apply(List(1,2), List(3,4))
// List[Int] = List(4, 5, 5, 6)

addXYApply[Option, Int].apply(1.some, 2.some)
// Option[Int] = Some(3)