立即使用计算出的可观察触发器在下拉菜单上进行敲除验证

Question

I have a problem very similar to Knockout Validation evaluates immediately on load only the solution presented there doesn't work for me, because I cannot initialize the observable with "" as it is a computed observable with logic in it.

I also tried binding it to the dropdown with:

value: computedObservable()

or:

value: function(){computedObservable}

or:

value: function(){computedObservable}()

instead of:

value: computedObservable

The observable itself is defined as:

viewModel.computedObservable = ko.pureComputed({
    write: function (value) {
        viewModel.observable(value);
    },
    read: function () {
        return viewModel.isObservableComputed() ? viewModel.existingModel().observable() : viewModel.observable();
    }
}).extend({ required: true });

How do I prevent validation on load (it is shown in a bootstrap modal) yet still trigger the validation on a save?

Answer 1

My current solution was to use conditional validation and set it to false initially and check another (required) field in the onlyIf, so this field only becomes required when the other has a value.

Better solutions are still very much welcome.