如何使用jQuery更改数据属性的子元素

Question

I want to change sub element of below data attribute

<div class="blue-shape"
data-actions='[{"event":"mouseenter","action":"jumptoslide","slide":"rs-18","delay":""}]'>

for this i have added below jquery code but it doesn't work

$(document).ready(function(){
    jQuery('.blue-shape').attr("data-actions",{event:'mouseenter', action:'jumptoslide', slide:'rs-16',delay:''});
});

.blue-shape is div class name where i want to change data attribute

Answer 1

You can pass a function as a second arguement and you can iterate over to change any value like:

 jQuery(document).ready(function($) { console.log($('.blue-shape').data('actions')); $('.blue-shape').attr("data-actions", function() { var arr = $(this).data('actions'), newArr = []; $.each(arr, function(i, obj){ if(obj.slide === "rs-18"){ obj.slide = "rs-16" } if(i === arr.length-1){ newArr.push(obj); } }); return newArr; }); console.log($('.blue-shape').data('actions')); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="blue-shape" data-actions='[{"event":"mouseenter","action":"jumptoslide","slide":"rs-18","delay":""}]'></div> 

Answer 2

jQuery.attr() expects second parameter to be string.

have a look at jQuery.data() also

 $('document').ready(function() { jQuery('.blue-shape') .attr("data-actions", "{event:'mouseenter', action:'jumptoslide', slide:'rs-16',delay:''}"); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <div class="blue-shape" data-actions='[{"event":"mouseenter","action":"jumptoslide","slide":"rs-18","delay":""}]'>DATA</div> 

Answer 3

You need to pass string in 2nd param or you can simply use data() method too like:

 console.log($('.blue-shape').data("actions")); $('.blue-shape').data("actions","[{event:'mouseenter', action:'jumptoslide', slide:'rs-16',delay:''}]"); console.log($('.blue-shape').data("actions")); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script> <div class="blue-shape" data-actions='[{"event":"mouseenter","action":"jumptoslide","slide":"rs-18","delay":""}]'> 

Answer 4

I just updated your jquery with this following code please check and vote if it works

$('document').ready(function(){
jQuery('.blue-shape').attr("data-actions","[{'event':'mouseenter', 'action':'jumptoslide', 'slide':'rs-16','delay':''}]");
});

For Reference

https://jsfiddle.net/jasonantho/6ehmded3/