Python正则表达式花括号多行

Question

I'm writing in python and let's say I have a file looking like this:

aaa 

aaa "word" --sdsdrrr2 --sds {

test test 
}

aaa "word2" --sdsdd sdsd {

    fffsd
    ssss
}

aaa "word3" -sdksdld sdsd

{

    sdsdd
    sdsddd
    sdsdddd }

now I want to parse output for "word2" including prefix and suffix, so output will be:

aaa "word2" --sdsdd sdsd {

    fffsd
    ssss
}

tried the following code:

f = open('/tmp/testt2')

for res in re.findall('aaa "word2" (.*?)}', f.read(), re.S):
    print res                                                                                                  

only got some of the matches without the beginning and the ending curly.

Please note:

• Number of lines between the curly brackets is unknown.
• Regex is a must
• Curly brackets positions are also unknown (can be spaced or not, new line or not etc) like in the example given above.

Thanks for any help,

Answer 1

You could do it like:

^(?=.*"word2") # ^ - start of the line with pos. lookahead
[^{]+        # anything not a {
{[^}]+}      # followed by {, anything in between and a closing }

See a demo on regex101.com as well as a working fiddle on ideone.com .