如果选择了任何行，则为JTable

Question

I am trying to figure out how to add logic to a JTable via an "if" statement that checks to see if ANY row is selected. I know how to check if a specific row is selected but I can't seem to figure out how to check all rows.

if(tbl.isRowSelected(0)){

Obviously that is checking for a specific row.

I've also tried something like

if(tbl.isRowSelected(0-2000)){

This did not work nor did I expect it to work.

The reason for this is that I'm setting up the table so that when the user clicks a row and then hits an "edit" button a second table will appear with more data related to the row they selected. (Gets complicated here with 2D arrays inside of a hash map but I first need to get by this simple problem).

Thanks for the help in advance!

Answer 1

This should be possible with a ListSelectionModel , which can be retrieved using JTable::getSelectionModel()

So you can call table.getSelectionModel().isSelectionEmpty() to find out if any row is selected.

Answer 2

Use :

 table.getSelectionModel().addListSelectionListener(new ListSelectionListener(){
        public void valueChanged(ListSelectionEvent event) {
            // do some actions here, for example
            // print first column value from selected row
            System.out.println(table.getValueAt(table.getSelectedRow(), 0).toString());
        }
    });

Answer 3

use table.getSelectedRow() it returns the index of the selected row and getSelectedColumn() return the selected columns

and there is getSelectedRows() it return index arrays of selected rows

int[] indexs=table_name.getSelectedRows();
//all the selected row are here no need to go throw 
//all your rows to see if they are selected or not
for(int index_row:rows){
   //you code here
 }