Spring 带分页的数据和本机查询

Question

In a web project, using latest spring-data (1.10.2) with a MySQL 5.6 database, I'm trying to use a native query with pagination but I'm experiencing an org.springframework.data.jpa.repository.query.InvalidJpaQueryMethodException at startup.

UPDATE : 20180306 This issue is now fixed in Spring 2.0.4 For those still interested or stuck with older versions check the related answers and comments for workarounds.

According to Example 50 at Using @Query from spring-data documentation this is possible specifying the query itself and a countQuery, like this:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
  Page<User> findByLastname(String lastname, Pageable pageable);
}

Out of curiosity, In NativeJpaQuery class I can see that it contains the following code to check if it's a valid jpa query:

public NativeJpaQuery(JpaQueryMethod method, EntityManager em, String queryString, EvaluationContextProvider evaluationContextProvider, SpelExpressionParser parser) {
   super(method, em, queryString, evaluationContextProvider, parser);
   JpaParameters parameters = method.getParameters();
   boolean hasPagingOrSortingParameter = parameters.hasPageableParameter() || parameters.hasSortParameter();
   boolean containsPageableOrSortInQueryExpression = queryString.contains("#pageable") || queryString.contains("#sort");
   if(hasPagingOrSortingParameter && !containsPageableOrSortInQueryExpression) {
       throw new InvalidJpaQueryMethodException("Cannot use native queries with dynamic sorting and/or pagination in method " + method);
   }
}

My query contains a Pageable parameter, so hasPagingOrSortingParameter is true , but it's also looking for a #pageable or #sort sequence inside the queryString , which I do not provide.

I've tried adding #pageable (it's a comment) at the end of my query, which makes validation to pass but then, it fails at execution saying that the query expects one additional parameter: 3 instead of 2.

Funny thing is that, if I manually change containsPageableOrSortInQueryExpression from false to true while running, the query works fine so I don't know why it's checking for that string to be at my queryString and I don't know how to provide it.

Any help would be much appreciated.

Update 01/30/2018 It seems that developers at spring-data project are working on a fix for this issue with a PR by Jens Schauder

Answer 1

My apologies in advance, this is pretty much summing up the original question and the comment from Janar , however...

I run into the same problem: I found the Example 50 of Spring Data as the solution for my need of having a native query with pagination but Spring was complaining on startup that I could not use pagination with native queries.

I just wanted to report that I managed to run successfully the native query I needed, using pagination, with the following code:

    @Query(value="SELECT a.* "
            + "FROM author a left outer join mappable_natural_person p on a.id = p.provenance_id "
            + "WHERE p.update_time is null OR (p.provenance_name='biblio_db' and a.update_time>p.update_time)"
            + "ORDER BY a.id \n#pageable\n", 
        /*countQuery="SELECT count(a.*) "
            + "FROM author a left outer join mappable_natural_person p on a.id = p.provenance_id "
            + "WHERE p.update_time is null OR (p.provenance_name='biblio_db' and a.update_time>p.update_time) \n#pageable\n",*/
        nativeQuery=true)
public List<Author> findAuthorsUpdatedAndNew(Pageable pageable);

The countQuery (that is commented out in the code block) is needed to use Page<Author> as the return type of the query, the newlines around the "#pageable" comment are needed to avoid the runtime error on the number of expected parameters (workaround of the workaround). I hope this bug will be fixed soon...

Answer 2

This is a hack for program using Spring Data JPA before Version 2.0.4 .

Code has worked with PostgreSQL and MySQL :

public interface UserRepository extends JpaRepository<User, Long> {

@Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 ORDER BY ?#{#pageable}",
       countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
       nativeQuery = true)
   Page<User> findByLastname(String lastname, Pageable pageable);   
}

ORDER BY ?#{#pageable} is for Pageable . countQuery is for Page<User> .

Answer 3

Just for the record, using H2 as testing database, and MySQL at runtime, this approach works (example is newest object in group ):

@Query(value = "SELECT t.* FROM t LEFT JOIN t AS t_newer " +
        "ON t.object_id = t_newer.object_id AND t.id < t_newer.id AND o_newer.user_id IN (:user_ids) " +
        "WHERE t_newer.id IS NULL AND t.user_id IN (:user_ids) " +
        "ORDER BY t.id DESC \n-- #pageable\n",
        countQuery = "SELECT COUNT(1) FROM t WHERE t.user_id IN (:user_ids) GROUP BY t.object_id, t.user_id",
        nativeQuery = true)
Page<T> findByUserIdInGroupByObjectId(@Param("user_ids") Set<Integer> userIds, Pageable pageable);

Spring Data JPA 1.10.5, H2 1.4.194, MySQL Community Server 5.7.11-log (innodb_version 5.7.11).

Answer 4

Try this:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 ORDER BY /*#pageable*/",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
  Page<User> findByLastname(String lastname, Pageable pageable);
}

( "/* */" for Oracle notation )

Answer 5

I have exact same symptom like @Lasneyx. My workaround for Postgres native query

@Query(value = "select * from users where user_type in (:userTypes) and user_context='abc'--#pageable\n", nativeQuery = true)
List<User> getUsersByTypes(@Param("userTypes") List<String> userTypes, Pageable pageable);

Answer 6

I use oracle database and I did not get the result but an error with generated comma which d-man speak about above.

Then my solution was:

Pageable pageable = new PageRequest(current, rowCount);

As you can see without order by when create Pagable.

And the method in the DAO:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE LASTNAME = ?1 /*#pageable*/ ORDER BY LASTNAME",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
  Page<User> findByLastname(String lastname, Pageable pageable);
 }

Answer 7

Both the following approaches work fine with MySQL for paginating native query. They doesn't work with H2 though. It will complain the sql syntax error.

• ORDER BY ?#{#pageable}
• ORDER BY a.id \\n#pageable\\n

Answer 8

I could successfully integrate Pagination in

spring-data-jpa-2.1.6

as follows.

@Query(
 value = “SELECT * FROM Users”, 
 countQuery = “SELECT count(*) FROM Users”, 
 nativeQuery = true)
Page<User> findAllUsersWithPagination(Pageable pageable);

Answer 9

使用 "ORDER BY id DESC \\n-- #pageable\\n " 而不是 "ORDER BY id \\n#pageable\\n" 对我的 MS SQL SERVER 有用

Answer 10

I am adding this answer just as a placeholder for those users who are using more recent versions of Spring Boot. On Spring Boot 2.4.3, I observed that none of the workaround were necessary, and the following code worked straight out of the box for me:

public interface UserRepository extends JpaRepository<User, Long> {
    @Query(value="SELECT * FROM USERS WHERE LASTNAME = ?1", nativeQuery=true)
    Page<User> findByLastname(String lastname, Pageable pageable);
}

The countQuery definition was not necessary, and a call to Page#getTotalElements() in fact already was returning the correct count, as returned by JPA's own internal count query.

The above code is extremely powerful, offering pagination made via a native query, yet which return results into actual Java entities (rather than the ugly and bulky List<Object[]> , which sometimes is necessary).

Answer 11

• Create your custom repository:

public interface ProductsCustomRepository extends JpaRepository<ProductResultEntity, Long> {
    @Query(
        value = "select tableA.id, tableB.bank_name from tableA join tableB on tableA.id = tableB.a_id where tableA.id = :id
        and (:fieldX is null or tableA.fieldX LIKE :fieldX)",
        countQuery = "select count(*) from tableA join tableB on tableA.id = tableB.a_id where tableA.id = :id
        and (:fieldX is null or tableA.fieldX LIKE :fieldX)",
        nativeQuery = true
    )
    Page<ProductResultEntity> search(@Param("id") Long aId,
        @Param("fieldX") String keyword, Pageable pageable
    );
}

• Create View as query of:

create view zzz as select * from tableA join tableB on tableA.id = tableB.a_id

• Generate ProductResultEntity from that zzz view (and delete view zzz when have done)
• Test call function and enjoy it:

productsRepository.search("123", "%BANK%", PageRequest.of(0, 5, Sort.by(Sort.Direction.ASC, "id")));

• Entity:

@Entity
public class ProductResultEntity {
    private Long id;
    private String bank;

    @Id
    @Column(name = "id", nullable = false)
    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    @Column(name = "bank_name", nullable = false)
    public String getBank() {
        return bank;
    }

    public void setBank(String bank) {
        this.bank = bank;
    }
}

Answer 12

It does work as below:

public interface UserRepository extends JpaRepository<User, Long> {
    @Query(value = "select * from (select (@rowid\\:=@rowid+1) as RN, u.* from USERS u, (SELECT @rowid\\:=0) as init where  LASTNAME = ?1) as total"+
        "where RN between ?#{#pageable.offset-1} and ?#{#pageable.offset + #pageable.pageSize}",
    countQuery = "SELECT count(*) FROM USERS WHERE LASTNAME = ?1",
    nativeQuery = true)
    Page<User> findByLastname(String lastname, Pageable pageable);
}

Answer 13

For me below worked in MS SQL

 @Query(value="SELECT * FROM ABC r where r.type in :type  ORDER BY RAND() \n-- #pageable\n ",nativeQuery = true)
List<ABC> findByBinUseFAndRgtnType(@Param("type") List<Byte>type,Pageable pageable);

Answer 14

@Query(value = "select * from user usr" +
  "left join apl apl on usr.user_id = apl.id" +
  "left join lang on lang.role_id = usr.role_id" +
  "where apl.scr_name like %:scrname% and apl.uname like %:uname and usr.role_id in :roleIds ORDER BY ?#{#pageable}",
  countQuery = "select count(*) from user usr" +
      "left join apl apl on usr.user_id = apl.id" +
      "left join lang on lang.role_id = usr.role_id" +
      "where apl.scr_name like %:scrname% and apl.uname like %:uname and usr.role_id in :roleIds",
  nativeQuery = true)
Page<AplUserEntity> searchUser(@Param("scrname") String scrname,@Param("uname") String  uname,@Param("roleIds") List<Long> roleIds,Pageable pageable);

Answer 15

Removing \\n#pageable\\n from both query and count query worked for me. Springboot version : 2.1.5.RELEASE DB : Mysql

Answer 16

This worked for me (I am using Postgres) in Groovy:

@RestResource(path="namespaceAndNameAndRawStateContainsMostRecentVersion", rel="namespaceAndNameAndRawStateContainsMostRecentVersion")
    @Query(nativeQuery=true,
            countQuery="""
            SELECT COUNT(1) 
            FROM 
            (
                SELECT
                ROW_NUMBER() OVER (
                    PARTITION BY name, provider_id, state
                    ORDER BY version DESC) version_partition,
                *
                FROM mydb.mytable
                WHERE
                (name ILIKE ('%' || :name || '%') OR (:name = '')) AND
                (namespace ILIKE ('%' || :namespace || '%') OR (:namespace = '')) AND
                (state = :state OR (:state = ''))
            ) t
            WHERE version_partition = 1
            """,
            value="""
            SELECT id, version, state, name, internal_name, namespace, provider_id, config, create_date, update_date 
            FROM 
            (
                SELECT 
                ROW_NUMBER() OVER (
                    PARTITION BY name, provider_id, state
                    ORDER BY version DESC) version_partition,
                *
                FROM mydb.mytable
                WHERE 
                (name ILIKE ('%' || :name || '%') OR (:name = '')) AND
                (namespace ILIKE ('%' || :namespace || '%') OR (:namespace = '')) AND
                (state = :state OR (:state = ''))       
            ) t            
            WHERE version_partition = 1             
            /*#{#pageable}*/
            """)
    public Page<Entity> findByNamespaceContainsAndNameContainsAndRawStateContainsMostRecentVersion(@Param("namespace")String namespace, @Param("name")String name, @Param("state")String state, Pageable pageable)

The key here was to use: /*#{#pageable}*/

It allows me to do sorting and pagination. You can test it by using something like this: http://localhost:8080/api/v1/entities/search/namespaceAndNameAndRawStateContainsMostRecentVersion?namespace=&name=&state=published&page=0&size=3&sort=name,desc

Watch out for this issue: Spring Pageable does not translate @Column name

Answer 17

You can use below code for h2 and MySQl

    @Query(value = "SELECT req.CREATED_AT createdAt, req.CREATED_BY createdBy,req.APP_ID appId,req.NOTE_ID noteId,req.MODEL model FROM SUMBITED_REQUESTS  req inner join NOTE note where req.NOTE_ID=note.ID and note.CREATED_BY= :userId "
        ,
         countQuery = "SELECT count(*) FROM SUMBITED_REQUESTS req inner join NOTE note WHERE req.NOTE_ID=note.ID and note.CREATED_BY=:userId",
        nativeQuery = true)
Page<UserRequestsDataMapper> getAllRequestForCreator(@Param("userId") String userId,Pageable pageable);

Answer 18

You can achieve it by using following code,

@Query(value = "SELECT * FROM users u WHERE  ORDER BY ?#{#pageable}", nativeQuery = true)
List<User> getUsers(String name, Pageable pageable);

Simply use ORDER BY ?#{#pageable} and pass page request to your method.

Enjoy!

Answer 19

@Query(value = "select " +
//"row_number() over (order by ba.order_num asc) as id, " +
"row_number() over () as id, " +
"count(ba.order_num),sum(ba.order_qty) as sumqty, " +
"ba.order_num, " +
"md.dpp_code,md.dpp_name, " +
"from biz_arrangement ba " +
"left join mst_dpp md on ba.dpp_code = md.dpp_code " +
"where 1 = 1 " +
"AND (:#{#flilter.customerCodeListCheck}='' OR ba.customer_code IN (:#{#flilter.customerCodeList})) " +
"AND (:#{#flilter.customerNameListCheck}='' OR ba.customer_name IN (:#{#flilter.customerNameList})) " +
"group by " +
"ba.order_num, " +
"md.dpp_code,md.dpp_name ",
countQuery = "select " +
"count ( " +
"distinct ( " +
"ba.order_num, " +
"md.dpp_code,md.dpp_name) " +
")" +
"from biz_arrangement ba " +
"left join mst_dpp md on ba.dpp_code = md.dpp_code " +
"where 1 = 1 " +
"AND (:#{#flilter.customerCodeListCheck}='' OR ba.customer_code IN (:#{#flilter.customerCodeList})) " +
"AND (:#{#flilter.customerNameListCheck}='' OR ba.customer_name IN (:#{#flilter.customerNameList})) ",
nativeQuery = true)
Page<Map<String, Object>> nativeQueryDynamicPageAndSort(@Param("flilter") Flilter flilter, Pageable pageable);

no need to add?#{#pageable}, the problem I got is when I use

row_number() over (order by ba.order_num asc) as id,

the input sort won't work when I change to

row_number() over () as id,

the dynamic input sort and pagination are both okay!

This is a group by query with a row id.

Answer 20

Replacing / #pageable / with ?#{#pageable} allow to do pagination. Adding PageableDefault allow you to set size of page Elements.