strcpy崩溃C程序

Question

Please tell me why strcpy fails. Im trying to copy the value str1 into one of the element of str2.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, char *argv[]) {

    char str1[]={"cat"}; //string
    char *str2[]={"mouse","dog"}; //array
    strcpy(str2[0],str1);       

    return 0;
}   

Answer 1

char str1[]={"cat"}; //string

is wrong in this context

"" is a replacement for tedious {'a','b'...'\\0'} .

Do either

char str1[]="cat";

or

char str1[]={'c','a','t','\0'};

Even then your code wouldn't work

strcpy(str2[0],str1); 

because you are trying to write into a read-only hard coded memory

as [ @michi ] mentioned in his comment.

But below would work

str2[0]=malloc(sizeof(str1)); // You allocate memory for str2[0];
strcpy(str2[0],str1); 
printf("str2[0] : %s\n",str2[0])

Also remember to free the allocated memory after use

free(str2[0]);