[英]Undefined array error (javascript) using php/ajax/json etc
I have a simple website here. 我这里有一个简单的网站。 It contains a div item with a css object inside. 它包含一个div项目,里面有一个css对象。 I'm trying to use ajax
and json
to run a php
script that will grab a value out of a text file and update the div item with said value. 我正在尝试使用ajax
和json
运行一个php
脚本,该脚本将从文本文件中获取值并使用所述值更新div项。
Problem is passing dataList[0]
to a the function replaceContentInContainer()
comes up as an undefined error in console. 问题是将dataList[0]
传递给函数replaceContentInContainer()
在控制台中出现为未定义的错误。
Here is the script that is throwing the error. 这是抛出错误的脚本。 It throws it as soon as dataList[0]
is referenced. 一引用dataList[0]
就抛出它。
<script>
setInterval(function()
{
$.getJSON('loadData.php', function(data){
var dataList = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
dataList = data.value;
var tempID = "tempDIV";
console.log('Good to go, data was loaded');
console.log(data);
ReplaceContentInContainer(tempID,dataList[0]);
}
}, 2000);
</script>
<script type="text/javascript"><!--
function ReplaceContentInContainer(id,content) {
var container = document.getElementById(id);
container.innerHTML = content;
}
//--></script>
the PHP file PHP文件
<?php
$lines = file("data.txt");
echo json_encode($lines);
?>
Data File format 'data.txt' 数据文件格式'data.txt'
78\n
82\n
33\n
etc...
Console output as follows 控制台输出如下
Good to go, data was loaded indexUpdate.php:30:5
Array [ "75 ", "34 ", "0 ", "0 ", "80 ", "31 ", "60 ", "72 ", "60 ", "70 ", 8 more… ] indexUpdate.php:31:5
TypeError: dataList is undefined
indexUpdate.php:32:5
Good to go, data was loaded indexUpdate.php:30:5
Array [ "75 ", "34 ", "0 ", "0 ", "80 ", "31 ", "60 ", "72 ", "60 ", "70 ", 8 more… ] indexUpdate.php:31:5
TypeError: dataList is undefined
It doesnt make sense why it thinks my array is undefined or at least why I am not allowed to define the element by a index. 它没有意义为什么它认为我的数组是未定义的,或者至少为什么我不允许通过索引定义元素。
dataList = data.value;
should be dataList = data;
应该是dataList = data;
as you're not returning an object, so there is no value
property. 因为你没有返回一个对象,所以没有value
属性。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.