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将字节数组作为Java系统软件包中的类加载

[英]Load byte array as a class in Java system packages

Anyone has idea how to class load a dynamically generated bytecode, which is expected to be in Java system class package (the package name starts with java.lang....). 任何人都知道如何对动态生成的字节码进行类加载,该字节码应放在Java系统类包中(包名称以java.lang ....开头)。

public class ByteCodeClassLoader extends ClassLoader{
    public static Class<?> run(String className, byte[] b){
         ....
         return load(className, b);
    }
    public   Class<?> load(String className,  byte[] b){
            .............
            Class<?> expClass = null;
            synchronized(this){
                expClass =defineClass(className, b, 0, b.length);
            }
            return expClass;

        return null;
    }

When I try to run the code (the className is java/lang/invoke/DYNGuardWithTestHandle0), it throws exception: 当我尝试运行代码( className为java / lang / invoke / DYNGuardWithTestHandle0)时,它将引发异常:

java.lang.NoClassDefFoundError: java/lang/invoke/DYNGuardWithTestHandle0
    at java.lang.ClassLoader.defineClassImpl(Native Method)
    at java.lang.ClassLoader.defineClass(ClassLoader.java:346)
    at java.lang.ClassLoader.defineClass(ClassLoader.java:283)
    at java.lang.invoke.ByteCodeClassLoader.load(ByteCodeClassLoader.java:83)
    at java.lang.invoke.ByteCodeClassLoader.run(ByteCodeClassLoader.java:54)

Thanks. 谢谢。


The given name is java/lang/invoke/DYNGuardWithTestHandle0, while the class name in the byte[] stream is java.lang.invoke.DYNGuardWithTestHandle0. 给定的名称为java / lang / invoke / DYNGuardWithTestHandle0,而byte []流中的类名称为java.lang.invoke.DYNGuardWithTestHandle0。 After making both consistent, the class loading would still fail because the package java.lang is protected package. 使两者一致之后,由于包java.lang是受保护的包,因此类加载仍将失败。

Javadoc of defineClass() says: defineClass() Javadoc说:

Throws NoClassDefFoundError if name is not equal to the binary name of the class specified by [byte array] 如果name不等于[byte array]指定的类的二进制名称,则抛出NoClassDefFoundError

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