如何从猫鼬查询中获得“干净”列表

Question

I execute a find query of mongoose:

UG.find({ "emailUser": req.body.emailUser }, "nameGroup" ,function (err, groups) {
    console.log(groups)
});

The result is "dirty" with some id,

How can I "clean" the result to a simple array -of only "namegroup"?

Answer 1

id is always returned by mongodb. You need to explicitly exclude it.

UG.find({ "emailUser": req.body.emailUser }, "nameGroup -id" ,function (err, groups) {
    console.log(groups)
});

For the _id field, you do not have to explicitly specify _id: 1 to return the _id field. The find() method always returns the _id field unless you specify _id: 0 to suppress the field.