[英]How to retrieve all permissions of a specific model in django?
By default each django model has 3 permissions (add, change, delete).默认情况下,每个 django 模型都有 3 个权限(添加、更改、删除)。 In a model I can define my custom permission to adds more.
在模型中,我可以定义我的自定义权限以添加更多。
class Company(models.Model):
owner = models.ForeignKey(User)
name = models.CharField(max_length=64, unique=True)
description = models.TextField(max_length=512)
created_on = models.DateTimeField(auto_now_add=timezone.now)
class Meta:
permissions = (
("erp_view_company", "Can see the company information"),
("erp_edit_company", "Can edit the company information"),
("erp_delete_company", "Can delete the company"),
)
When you migrate, these permissions are automatically created at DB level.迁移时,这些权限会在数据库级别自动创建。 How can you retrieve all the permissions from a model?
如何从模型中检索所有权限?
# retrieves the permissions
permissions = Permission.objects.filter(get_all_permissions_of_model_Company)
# adds permissions to group
group = Group.objects.create(name='foo', permissions=permissions)
# adds user to group
user.groups.add(group)
I would suggest you something like this:我建议你这样做:
all_permissions = Permission.objects.filter(content_type__app_label='app label', content_type__model='lower case model name')
Retrieving model's app_label
:检索模型的
app_label
:
Company._meta.app_label
Retrieving model's lower case name:检索模型的小写名称:
Company._meta.model_name
Also, you can retrieve a ContentType
instance representing a model :此外,您还可以检索表示模型的
ContentType
实例:
ContentType.objects.get_for_model(Company)
Since ContentType
uses a cache, it is quite acceptable.由于
ContentType
使用了缓存,所以完全可以接受。 Thus, there is another way to achieve what you need:因此,还有另一种方法可以实现您的需求:
content_type = ContentType.objects.get_for_model(Company)
all_permissions = Permission.objects.filter(content_type=content_type)
you can check on codename
field which will be something like: 'change_company'
etc ...您可以检查
codename
字段,该字段类似于: 'change_company'
等...
model_name = 'company'
all_perms_on_this_modal = Permission.objects.filter(codename__contains=model_name)
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